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Let’s check out your problem:
Solve:
∫
ln
(
x
)
+
5
x
d
x
\int \frac{\ln(x) + 5}{x} \, dx
∫
x
l
n
(
x
)
+
5
d
x
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Math Problems
Calculus
Find indefinite integrals using the substitution and by parts
Full solution
Q.
Solve:
∫
ln
(
x
)
+
5
x
d
x
\int \frac{\ln(x) + 5}{x} \, dx
∫
x
l
n
(
x
)
+
5
d
x
Recognize Split Integral:
Recognize that the integral can be split into two separate integrals.
\newline
I
=
∫
(
ln
(
x
)
+
5
)
/
x
d
x
I = \int(\ln(x) + 5)/x \, dx
I
=
∫
(
ln
(
x
)
+
5
)
/
x
d
x
\newline
I
=
∫
ln
(
x
)
/
x
d
x
+
∫
5
/
x
d
x
I = \int\ln(x)/x \, dx + \int5/x \, dx
I
=
∫
ln
(
x
)
/
x
d
x
+
∫
5/
x
d
x
Integrate
ln
(
x
)
/
x
\ln(x)/x
ln
(
x
)
/
x
:
Integrate the first part
∫
ln
(
x
)
/
x
d
x
\int \ln(x)/x \, dx
∫
ln
(
x
)
/
x
d
x
using the fact that the integral of
ln
(
x
)
/
x
\ln(x)/x
ln
(
x
)
/
x
is a known integral.
\newline
I
1
=
∫
ln
(
x
)
/
x
d
x
=
(
ln
(
x
)
)
2
/
2
I_1 = \int \ln(x)/x \, dx = (\ln(x))^2/2
I
1
=
∫
ln
(
x
)
/
x
d
x
=
(
ln
(
x
)
)
2
/2
Integrate
5
/
x
5/x
5/
x
:
Integrate the second part
∫
5
x
d
x
\int \frac{5}{x} \, dx
∫
x
5
d
x
using the fact that the integral of
1
/
x
1/x
1/
x
is
ln
∣
x
∣
\ln|x|
ln
∣
x
∣
.
I
2
=
∫
5
x
d
x
=
5
ln
∣
x
∣
I_2 = \int \frac{5}{x} \, dx = 5\ln|x|
I
2
=
∫
x
5
d
x
=
5
ln
∣
x
∣
Combine Final Integral:
Combine the results from Step
2
2
2
and Step
3
3
3
to get the final indefinite integral.
\newline
I
=
I
1
+
I
2
+
C
I = I_1 + I_2 + C
I
=
I
1
+
I
2
+
C
\newline
I
=
(
ln
(
x
)
)
2
2
+
5
ln
∣
x
∣
+
C
I = \frac{(\ln(x))^2}{2} + 5\ln|x| + C
I
=
2
(
l
n
(
x
)
)
2
+
5
ln
∣
x
∣
+
C
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\newline
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