Simplify Expression: Let's start by simplifying the expression under the square root in the denominator. We can factor the expression as a perfect square trinomial.52x+3⋅5x+1=(5x+1)2
Rewrite Integral: Now, we rewrite the integral using the simplified expression under the square root. ∫52x+3⋅5x+15xdx=∫5x+15xdx
Perform Substitution: We can now perform a substitution to simplify the integral further. Let u=5x+1. Then, we need to find du in terms of dx. To find du, we differentiate u with respect to x. dxdu=dxd(5x+1)=ln(5)⋅5x So, du=ln(5)⋅5xdx
Express dx in Terms: We can now express dx in terms of du and 5x. dx=ln(5)⋅5xdu Substitute this expression for dx and u into the integral. ∫5x+15xdx=∫ln(5)⋅5x5xudu
Cancel Terms: Simplify the integral by canceling out the 5x terms.∫ln(5)⋅5x5xudu = ∫ln(5)1udu
Integrate 1/u: Now we can integrate 1/u with respect to u. ∫(1/(ln(5))du/u)=(1/ln(5))⋅∫(1/udu) The integral of 1/u with respect to u is ln∣u∣.
Perform Integration: Perform the integration to find the indefinite integral.(ln(5)1)∫u1du=(ln(5)1)ln∣u∣+C
Substitute Back: Substitute back the original expression for u to get the final answer.(ln(5)1)∗ln∣u∣+C=(ln(5)1)∗ln∣5(x)+1∣+C
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