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Given 
x > 0 and 
y > 0, select the expression that is equivalent to

sqrt(-100x^(7)y^(15))

10 ix^((7)/(2))y^((15)/(2))

-10x^((7)/(2))y^((15)/(2))

10 ix^(14)y^(30)

-10x^(14)y^(30)

Given x>0 and y>0 , select the expression that is equivalent to\newline100x7y15 \sqrt{-100 x^{7} y^{15}} \newline10ix72y152 10 i x^{\frac{7}{2}} y^{\frac{15}{2}} \newline10x72y152 -10 x^{\frac{7}{2}} y^{\frac{15}{2}} \newline10ix14y30 10 i x^{14} y^{30} \newline10x14y30 -10 x^{14} y^{30}

Full solution

Q. Given x>0 x>0 and y>0 y>0 , select the expression that is equivalent to\newline100x7y15 \sqrt{-100 x^{7} y^{15}} \newline10ix72y152 10 i x^{\frac{7}{2}} y^{\frac{15}{2}} \newline10x72y152 -10 x^{\frac{7}{2}} y^{\frac{15}{2}} \newline10ix14y30 10 i x^{14} y^{30} \newline10x14y30 -10 x^{14} y^{30}
  1. Rewrite using imaginary unit: We are given the expression 100x7y15\sqrt{-100x^{7}y^{15}}. The square root of a negative number involves the imaginary unit ii, where i2=1i^2 = -1. Therefore, we can rewrite the expression as 1×100x7y15\sqrt{-1} \times \sqrt{100x^{7}y^{15}}.
  2. Factor out terms: The square root of 1-1 is the imaginary unit ii, and the square root of 100100 is 1010. We can then factor out these terms to get 10ix7y1510i \cdot \sqrt{x^{7}y^{15}}.
  3. Express exponents as squares: Next, we can express x(7)x^{(7)} as x(7/2)2x^{(7/2)^2} and y(15)y^{(15)} as y(15/2)2y^{(15/2)^2} to prepare them to be taken out of the square root, since a2=a\sqrt{a^2} = a.
  4. Take square roots: Taking the square root of x(7/2)2x^{(7/2)^2} and y(15/2)2y^{(15/2)^2}, we get x7/2x^{7/2} and y15/2y^{15/2} respectively. Therefore, the expression becomes 10i×x7/2×y15/210i \times x^{7/2} \times y^{15/2}.
  5. Final expression: The final expression is 10i×x72×y15210i \times x^{\frac{7}{2}} \times y^{\frac{15}{2}}, which is equivalent to the given expression 100x7y15\sqrt{-100x^{7}y^{15}}.