Q. Find the value of ∫79x−112dx. Write your answer as the logarithm of a single number in simplest form.Answer: ln(□)
Apply Fundamental Theorem: We apply the fundamental theorem of calculus to evaluate the definite integral: ∫79x−112dx=[2ln∣x−11∣] from 7 to 9.We substitute the upper and lower limits into the antiderivative:2ln∣9−11∣−2ln∣7−11∣.
Simplify with Substitution: Now we simplify the expression by substituting the values: 2ln∣−2∣−2ln∣−4∣.Since the logarithm of a negative number is not defined in the real number system, we can remove the absolute value bars because both −2 and −4 are negative and will become positive inside the absolute value.This gives us:2ln(2)−2ln(4).
Further Logarithm Simplification: We can further simplify the expression using logarithm properties: 2ln(2)−2ln(4)=2ln(2)−2ln(22).Since ln(22)=2ln(2), the expression becomes:2ln(2)−2(2ln(2)).
Distribute and Simplify: Now we simplify the expression by distributing the 2 in the second term: 2ln(2)−4ln(2). This simplifies to: −2ln(2).
Final Answer: The final answer is the negative of two times the natural logarithm of 2: Answer: ln(2−2). We can use the property of logarithms that ln(ab)=b⋅ln(a) to write the answer as a single logarithm: ln(2−2)=ln(41).
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