Identify integral: Identify the integral to be solved.We need to evaluate the integral of the function 6xcos(4x) with respect to x, which is written as ∫6xcos(4x)dx.
Use integration by parts: Use integration by parts.Integration by parts is given by the formula ∫udv=uv−∫vdu, where u and dv are parts of the integrand. We choose u and dv as follows:Let u=6x, which implies du=6dx.Let dv=cos(4x)dx, which implies v=41sin(4x) after integrating with respect to x.
Apply integration by parts: Apply the integration by parts formula.Using the chosen u and dv, we have:∫6xcos(4x)dx=uv−∫vdu=(6x)(41)sin(4x)−∫(41)sin(4x)(6dx)=(23)xsin(4x)−(23)∫sin(4x)dx
Integrate remaining integral: Integrate the remaining integral.Now we need to integrate ∫sin(4x)dx. The antiderivative of sin(4x) with respect to x is −41cos(4x). So we have:\frac{3}{2}\int \sin(4x) \, dx = \frac{3}{2}\left(-\frac{1}{4}\cos(4x)\right) + C\(\newline= -\frac{3}{8}\cos(4x) + C\), where C is the constant of integration.
Combine final answer: Combine the results to get the final answer.Putting it all together, we have:∫6xcos(4x)dx=(23)xsin(4x)−(83)cos(4x)+C
More problems from Find indefinite integrals using the substitution and by parts