Choose u and dv: Let's use integration by parts to solve the integral of 2x2e−x with respect to x. Integration by parts is given by the formula ∫udv=uv−∫vdu, where u and dv are parts of the integrand that we choose. We will let u=x2 and dv=2e−xdx. Then we need to find du and dv0.First, we calculate du by differentiating u with respect to x:dv4.Next, we find dv0 by integrating dv:dv7.To integrate dv0, we use the fact that the integral of dv9 is 2x2e−x0, so:2x2e−x1.
Apply integration by parts: Now that we have u, du, v, and dv, we can apply the integration by parts formula:∫2x2e(−x)dx=uv−∫vdu=x2(−2e(−x))−∫(−2e(−x))(2x)dx=−2x2e(−x)−∫(−4xe(−x))dx.We now have a new integral to solve, which is ∫(−4xe(−x))dx. We will use integration by parts again for this new integral.
New integral to solve: For the new integral ∫(−4xe−x)dx, we will let u=−4x and dv=e−xdx. Then we need to find du and v.First, we calculate du by differentiating u with respect to x:du=d(−4x)/dx=−4dx.Next, we find v by integrating u=−4x0:u=−4x1.To integrate v, we use the fact that the integral of u=−4x3 is u=−4x4, so:u=−4x5.
Apply integration by parts again: Now we apply the integration by parts formula to the new integral: ∫(−4xe−x)dx=uv−∫vdu= (−4x)(−e−x)−∫(−e−x)(−4)dx= 4xe−x−∫4e−xdx.The remaining integral ∫4e−xdx is straightforward to solve, as it is a constant multiple of the integral of e−x, which is −e−x.
Solve remaining integral: We integrate ∫4e−xdx: ∫4e−xdx=4∫e−xdx=4(−e−x)=−4e−x.Now we can combine all the parts we have integrated:−2x2e−x−(4xe−x−(−4e−x)).
Combine integrated parts: Simplify the expression by distributing the negative sign and combining like terms: −2x2e−x−4xe−x+4e−x.This is the antiderivative of the original integral. We also need to add the constant of integration, which we will denote as C.
Simplify expression: The final answer for the integral is: ∫2x2e−xdx=−2x2e−x−4xe−x+4e−x+C.
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