Choose u and dv: To solve the integral of xe2x with respect to x, we will use integration by parts, which is given by the formula ∫udv=uv−∫vdu, where u and dv are parts of the integrand that we choose.
Apply integration by parts: Let's choose u=x (which will be differentiated) and dv=e2xdx (which will be integrated). Differentiating u gives us du=dx, and integrating dv gives us v=21e2x.
Integrate dv: Now we apply the integration by parts formula: ∫xe2xdx=uv−∫vdu. Substituting the chosen parts, we get $\int x e^{\(2\)x} dx = x \left(\frac{\(1\)}{\(2\)}\right)e^{\(2\)x} - \int \left(\frac{\(1\)}{\(2\)}\right)e^{\(2\)x} dx.
Substitute back: Next, we integrate \((1/2)e^{2x}\) with respect to \(x\), which gives us \((1/2)\cdot(1/2)e^{2x} = (1/4)e^{2x}\).
Final result: Substituting this back into our equation, we have \(\int x e^{2x} dx = \left(\frac{1}{2}\right) x e^{2x} - \left(\frac{1}{4}\right) e^{2x} + C\), where \(C\) is the constant of integration.
Final result: Substituting this back into our equation, we have \(\int xe^{2x}\,dx = \frac{1}{2}xe^{2x} - \frac{1}{4}e^{2x} + C\), where \(C\) is the constant of integration.Therefore, the integral of \(xe^{2x}\) with respect to \(x\) is \(\frac{1}{2}xe^{2x} - \frac{1}{4}e^{2x} + C\).
More problems from Find indefinite integrals using the substitution and by parts