Evaluate the integral. int x(x-4)(2x+5)dx Answer:

Expand integrand: Let's expand the integrand before integrating. I = ∫x(x-4)(2x+5)dx = ∫(2x^3 - 8x^2 + 5x^2 - 20x)dx = ∫(2x^3 - 3x^2 - 20x)dxIntegrate each term: Now we integrate each term separately. I = ∫(2x^3)dx - ∫(3x^2)dx - ∫(20x)dx = (2/4)x^4 - (3/3)x^3 - (20/2)x^2 + C = (1/2)x^4 - x^3 - 10x^2 + C

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Evaluate the integral.

int x(x-4)(2x+5)dx
Answer:

Evaluate the integral. $\newline$ $\int x(x-4)(2 x+5) \mathrm{d} x$ $\newline$ Answer:

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Calculus

Find indefinite integrals using the substitution and by parts

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Q. Evaluate the integral.

\newline

\int x(x-4)(2 x+5) \mathrm{d} x

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Answer:

Expand integrand: Let's expand the integrand before integrating. $\newline$ $I = \int x(x-4)(2x+5)\,dx$ $\newline$ $= \int (2x^3 - 8x^2 + 5x^2 - 20x)\,dx$ $\newline$ $= \int (2x^3 - 3x^2 - 20x)\,dx$
Integrate each term: Now we integrate each term separately. $\newline$ $I = \int(2x^3)\,dx - \int(3x^2)\,dx - \int(20x)\,dx$ $\newline$ $= \frac{2}{4}x^4 - \frac{3}{3}x^3 - \frac{20}{2}x^2 + C$ $\newline$ $= \frac{1}{2}x^4 - x^3 - 10x^2 + C$