Evaluate the integral. int(28x^(4)-12x^(3)-2x^(2))/(x)dx Answer:

Simplify the integrand: We are given the integral: int((28x^(4)-12x^(3)-2x^(2))/(x))dx First, simplify the integrand by dividing each term by x. (28x^(4)-12x^(3)-2x^(2))/(x) = 28x^(4-1) - 12x^(3-1) - 2x^(2-1) = 28x^3 - 12x^2 - 2xIntegrate each term separately: Now, integrate each term separately. int(28x^3 - 12x^2 - 2x)dx = int(28x^3)dx - int(12x^2)dx - int(2x)dx = (28/4)x^(3+1) - (12/3)x^(2+1) - (2/2)x^(1+1) + C = 7x^4 - 4x^3 - x^2 + C

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Evaluate the integral.

int(28x^(4)-12x^(3)-2x^(2))/(x)dx
Answer:

Evaluate the integral. $\newline$ $\int \frac{28 x^{4}-12 x^{3}-2 x^{2}}{x} \mathrm{~d} x$ $\newline$ Answer:

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Math Problems

Calculus

Find indefinite integrals using the substitution

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Q. Evaluate the integral.

\newline

\int \frac{28 x^{4}-12 x^{3}-2 x^{2}}{x} \mathrm{~d} x

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Answer:

Simplify the integrand: We are given the integral: $\int\left(\frac{28x^{4}-12x^{3}-2x^{2}}{x}\right)dx$ First, simplify the integrand by dividing each term by x. $\frac{28x^{4}-12x^{3}-2x^{2}}{x} = 28x^{4-1} - 12x^{3-1} - 2x^{2-1}$ = $28x^3 - 12x^2 - 2x$
Integrate each term separately: Now, integrate each term separately. $\newline$ $\int(28x^3 - 12x^2 - 2x)\,dx = \int(28x^3)\,dx - \int(12x^2)\,dx - \int(2x)\,dx$ $\newline$ $= \frac{28}{4}x^{3+1} - \frac{12}{3}x^{2+1} - \frac{2}{2}x^{1+1} + C$ $\newline$ $= 7x^4 - 4x^3 - x^2 + C$