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Let’s check out your problem:
Evaluate the integral.
\newline
∫
(
28
x
3
+
6
x
2
)
d
x
\int\left(28 x^{3}+6 x^{2}\right) d x
∫
(
28
x
3
+
6
x
2
)
d
x
\newline
Answer:
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Math Problems
Calculus
Find indefinite integrals using the substitution
Full solution
Q.
Evaluate the integral.
\newline
∫
(
28
x
3
+
6
x
2
)
d
x
\int\left(28 x^{3}+6 x^{2}\right) d x
∫
(
28
x
3
+
6
x
2
)
d
x
\newline
Answer:
Given integral:
We are given the integral to evaluate:
∫
(
28
x
3
+
6
x
2
)
d
x
\int(28x^{3}+6x^{2})dx
∫
(
28
x
3
+
6
x
2
)
d
x
We will integrate term by term.
Integrating
28
x
3
28x^3
28
x
3
:
The integral of
28
x
3
28x^3
28
x
3
with respect to
x
x
x
is:
∫
(
28
x
3
)
d
x
=
(
28
4
)
x
3
+
1
=
7
x
4
\int(28x^{3})dx = \left(\frac{28}{4}\right)x^{3+1} = 7x^4
∫
(
28
x
3
)
d
x
=
(
4
28
)
x
3
+
1
=
7
x
4
Integrating
6
x
2
6x^2
6
x
2
:
The integral of
6
x
2
6x^2
6
x
2
with respect to
x
x
x
is:
\newline
∫
(
6
x
2
)
d
x
=
(
6
3
)
x
2
+
1
=
2
x
3
\int(6x^{2})dx = \left(\frac{6}{3}\right)x^{2+1} = 2x^3
∫
(
6
x
2
)
d
x
=
(
3
6
)
x
2
+
1
=
2
x
3
Adding integrals and constant:
Now we add the two integrals together and include the constant of integration
C
C
C
:
7
x
4
+
2
x
3
+
C
7x^4 + 2x^3 + C
7
x
4
+
2
x
3
+
C
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\newline
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x
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(
−
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x
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d
x
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