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Evaluate the integral and express your answer in simplest form.

int(-7)/(xsqrt(x^(2)-1))dx
Answer:

Evaluate the integral and express your answer in simplest form.\newline7xx21dx \int \frac{-7}{x \sqrt{x^{2}-1}} d x \newlineAnswer:

Full solution

Q. Evaluate the integral and express your answer in simplest form.\newline7xx21dx \int \frac{-7}{x \sqrt{x^{2}-1}} d x \newlineAnswer:
  1. Identify Substitution: Let's start by identifying a substitution that can simplify the integral. We notice that the denominator has the expression x21\sqrt{x^2-1}, which suggests a trigonometric substitution. Specifically, we can use the substitution x=sec(θ)x = \sec(\theta), because then x21\sqrt{x^2-1} would become sec2(θ)1=tan(θ)\sqrt{\sec^2(\theta)-1} = \tan(\theta). Let's perform this substitution.
  2. Find dxdx in terms of d(θ)d(\theta): First, we need to find dxdx in terms of d(θ)d(\theta). Since x=sec(θ)x = \sec(\theta), we take the derivative of both sides with respect to θ\theta to get dxd(θ)=sec(θ)tan(θ)\frac{dx}{d(\theta)} = \sec(\theta)\tan(\theta). Therefore, dx=sec(θ)tan(θ)d(θ)dx = \sec(\theta)\tan(\theta)d(\theta).
  3. Perform Substitution: Now we substitute x=sec(θ)x = \sec(\theta) and dx=sec(θ)tan(θ)d(θ)dx = \sec(\theta)\tan(\theta)d(\theta) into the integral. The integral becomes:\newline7sec(θ)tan(θ)sec(θ)tan(θ)d(θ)\int\frac{-7}{\sec(\theta)\tan(\theta)} \cdot \sec(\theta)\tan(\theta)d(\theta)\newlineThis simplifies to:\newline(7)d(θ)\int(-7)d(\theta)
  4. Integrate Constant: The integral of a constant is just the constant times the variable of integration. So we have: 7×θ+C-7 \times \theta + C, where CC is the constant of integration.
  5. Back-Substitute for xx: Now we need to back-substitute to get our answer in terms of xx. We originally set x=sec(θ)x = \sec(\theta), so we need to solve for θ\theta. We can do this by taking the inverse secant of both sides: θ=arcsec(x)\theta = \text{arcsec}(x).
  6. Final Answer: Substituting θ\theta back into our integral result, we get:\newline7×arcsec(x)+C-7 \times \text{arcsec}(x) + C\newlineThis is our final answer in terms of xx.