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Let’s check out your problem:
Evaluate the integral and express your answer in simplest form.
\newline
∫
−
5
25
+
25
x
2
d
x
\int \frac{-5}{25+25 x^{2}} d x
∫
25
+
25
x
2
−
5
d
x
\newline
Answer:
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Math Problems
Calculus
Find indefinite integrals using the substitution
Full solution
Q.
Evaluate the integral and express your answer in simplest form.
\newline
∫
−
5
25
+
25
x
2
d
x
\int \frac{-5}{25+25 x^{2}} d x
∫
25
+
25
x
2
−
5
d
x
\newline
Answer:
Factor out constant:
Simplify the integral by factoring out the constant
25
25
25
from the denominator.
\newline
∫
−
5
25
+
25
x
2
d
x
=
∫
−
5
/
25
1
+
x
2
d
x
=
∫
−
1
/
5
1
+
x
2
d
x
\int\frac{-5}{25+25x^{2}}dx = \int\frac{-5/25}{1+x^{2}}dx = \int\frac{-1/5}{1+x^{2}}dx
∫
25
+
25
x
2
−
5
d
x
=
∫
1
+
x
2
−
5/25
d
x
=
∫
1
+
x
2
−
1/5
d
x
Recognize arctangent form:
Recognize that the integral is now in the form of the arctangent function derivative.
∫
(
−
1
5
)
/
(
1
+
x
2
)
d
x
=
−
1
5
∫
(
1
1
+
x
2
)
d
x
\int(-\frac{1}{5})/(1+x^{2})dx = -\frac{1}{5} \int(\frac{1}{1+x^{2}})dx
∫
(
−
5
1
)
/
(
1
+
x
2
)
d
x
=
−
5
1
∫
(
1
+
x
2
1
)
d
x
Evaluate using arctangent:
Evaluate the integral using the arctangent function.
\newline
−
1
5
∫
1
1
+
x
2
d
x
=
−
1
5
arctan
(
x
)
+
C
-\frac{1}{5} \int \frac{1}{1+x^{2}}dx = -\frac{1}{5} \arctan(x) + C
−
5
1
∫
1
+
x
2
1
d
x
=
−
5
1
arctan
(
x
)
+
C
Write final answer:
Write the final answer.
\newline
Answer:
−
1
5
⋅
arctan
(
x
)
+
C
-\frac{1}{5} \cdot \arctan(x) + C
−
5
1
⋅
arctan
(
x
)
+
C
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\newline
∫
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x
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x
d
x
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∫
6
x
2
5
3
x
d
x
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\newline
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∫
−
6
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\newline
∫
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x
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∫
6
x
2
2
3
x
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x
\newline
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Evaluate the integral.
\newline
∫
−
3
x
sin
(
−
2
x
)
d
x
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∫
−
3
x
sin
(
−
2
x
)
d
x
\newline
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