Q. Evaluate ∫39x−22x2−13x+15dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
Perform Polynomial Long Division: Perform polynomial long division to simplify the integrand.We need to divide the polynomial 2x2−13x+15 by x−2.
Split Integrals: Split the integral into two separate integrals.∫(2x−3+x−29)dx=∫(2x−3)dx+∫(x−29)dx
Integrate Terms Separately: Integrate each term separately.The integral of 2x−3 is x2−3x, and the integral of x−29 is 9ln∣x−2∣.∫(2x−3)dx=x2−3x∫(x−29)dx=9ln∣x−2∣
Combine Integrals: Combine the integrals and evaluate from 3 to 9. The combined integral is (x2−3x+9ln∣x−2∣) from 3 to 9.
Evaluate Definite Integral: Evaluate the definite integral.Plug in the upper limit 9 and the lower limit 3 into the antiderivative and subtract.F(9)=92−3⋅9+9ln∣9−2∣F(3)=32−3⋅3+9ln∣3−2∣
Perform Calculations for Limits: Perform the calculations for each limit.F(9)=81−27+9ln(7)F(3)=9−9+9ln(1)
Subtract Limits: Subtract F(3) from F(9) to get the final result.F(9)−F(3)=(81−27+9ln(7))−(9−9+9ln(1))
Simplify Expression: Simplify the expression.F(9)−F(3)=81−27+9ln(7)−9+9+0F(9)−F(3)=54+9ln(7)
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