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Evaluate 
int_(2)^(3)(4x^(2)-15 x-3)/(x-4)dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).

Evaluate 234x215x3x4dx \int_{2}^{3} \frac{4 x^{2}-15 x-3}{x-4} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).

Full solution

Q. Evaluate 234x215x3x4dx \int_{2}^{3} \frac{4 x^{2}-15 x-3}{x-4} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
  1. Perform Polynomial Long Division: We will first perform polynomial long division to simplify the integrand (4x215x3)/(x4)(4x^2 - 15x - 3) / (x - 4). Dividing 4x24x^2 by xx gives us 4x4x. Multiplying 4x4x by (x4)(x - 4) gives us 4x216x4x^2 - 16x. Subtracting this from the original numerator, we get 4x215x3(4x216x)=x+34x^2 - 15x - 3 - (4x^2 - 16x) = x + 3. So, the quotient is 4x+14x + 1 and the remainder is x+3x + 3. The integral can now be rewritten as the integral of 4x+14x + 1 plus the integral of the remainder over 4x24x^211.
  2. Integrate Simplified Expression Term by Term: Now we will integrate the simplified expression term by term. The integral of 4x4x is 2x22x^2, and the integral of 11 is xx. For the remainder, we have the integral of (x+3)/(x4)(x + 3) / (x - 4). We can split this into two separate integrals: the integral of x/(x4)x / (x - 4) and the integral of 3/(x4)3 / (x - 4).
  3. Evaluate Antiderivative from 22 to 33: The integral of x/(x4)x / (x - 4) can be simplified by recognizing that the derivative of the denominator (x4)(x - 4) is 11, which matches the numerator xx after adjusting for the constant shift. Therefore, the integral of x/(x4)x / (x - 4) is lnx4\ln|x - 4|. The integral of 3/(x4)3 / (x - 4) is 33 times the integral of 3300, which is 3311.
  4. Combine Logarithmic Terms: Combining all the terms, the integral becomes 2x2+x+lnx4+3lnx42x^2 + x + \ln|x - 4| + 3\ln|x - 4|. Since we want to condense the logarithms into a single logarithm, we use the property that ln(a)+ln(b)=ln(ab)\ln(a) + \ln(b) = \ln(ab) to combine the logarithmic terms. This gives us 2x2+x+ln(x4)4.2x^2 + x + \ln|(x - 4)^4|.
  5. Simplify Integral at Upper and Lower Limits: Now we need to evaluate the antiderivative from 22 to 33. We plug in the upper limit of 33 into the antiderivative to get 2(3)2+3+ln(34)42(3)^2 + 3 + \ln|(3 - 4)^4|, which simplifies to 18+3+ln(1)4=21+ln118 + 3 + \ln|(-1)^4| = 21 + \ln|1|. Then we plug in the lower limit of 22 into the antiderivative to get 2(2)2+2+ln(24)42(2)^2 + 2 + \ln|(2 - 4)^4|, which simplifies to 8+2+ln(2)4=10+ln168 + 2 + \ln|(-2)^4| = 10 + \ln|16|.
  6. Subtract Values at Upper and Lower Limits: Subtracting the value at the lower limit from the value at the upper limit, we get (21+ln1)(10+ln16)(21 + \ln|1|) - (10 + \ln|16|). Since ln1\ln|1| is 00, this simplifies to 2110ln16=11ln1621 - 10 - \ln|16| = 11 - \ln|16|.
  7. Final Answer: The final answer in simplest form is 11ln16.11 - \ln|16|.