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Calculate the integral and write the answer in simplest form.

int(5x^(-2)-2)dx
Answer:

Calculate the integral and write the answer in simplest form.\newline(5x22)dx \int\left(5 x^{-2}-2\right) d x \newlineAnswer:

Full solution

Q. Calculate the integral and write the answer in simplest form.\newline(5x22)dx \int\left(5 x^{-2}-2\right) d x \newlineAnswer:
  1. Identify Integral: Identify the integral to be solved.\newlineWe need to find the indefinite integral of the function 5x225x^{-2}-2 with respect to xx.\newlineThe integral is written as (5x22)dx\int(5x^{-2}-2)\,dx.
  2. Break Down: Break down the integral into simpler parts.\newlineThe integral of a sum is the sum of the integrals, so we can write:\newline(5x22)dx=5x2dx2dx\int(5x^{-2}-2)\,dx = \int 5x^{-2}\,dx - \int 2\,dx.
  3. Integrate Separately: Integrate each term separately.\newlineFor the first term, 5x2dx\int 5x^{-2}\,dx, we use the power rule of integration, which states that xndx=xn+1n+1+C\int x^n \,dx = \frac{x^{n+1}}{n+1} + C, where n1n \neq -1.\newlineApplying the power rule, we get:\newline5x2dx=5×x2dx=5×(x1)+C1=5x+C1\int 5x^{-2}\,dx = 5 \times \int x^{-2}\,dx = 5 \times (-x^{-1}) + C_1 = -\frac{5}{x} + C_1, where C1C_1 is a constant of integration.
  4. Integrate Second Term: Integrate the second term.\newlineFor the second term, 2dx\int 2\,dx, the integral of a constant is the constant times the variable of integration plus another constant of integration.\newlineSo, 2dx=2x+C2\int 2\,dx = 2x + C_2, where C2C_2 is another constant of integration.
  5. Combine Results: Combine the results of the two integrals.\newlineCombining the results from Step 33 and Step 44, we get:\newline(5x22)dx=5x+2x+C1+C2.\int(5x^{-2}-2)dx = -\frac{5}{x} + 2x + C_1 + C_2.\newlineSince C1C_1 and C2C_2 are arbitrary constants, we can combine them into a single constant, CC.\newlineTherefore, the integral is:\newline(5x22)dx=5x+2x+C.\int(5x^{-2}-2)dx = -\frac{5}{x} + 2x + C.