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Assuming
x and
y are both positive, write the following expression in simplest radical form.

2sqrt(25x^(6)y^(5))
Answer:

Assuming $x$ and $y$ are both positive, write the following expression in simplest radical form. $\newline$ $2 \sqrt{25 x^{6} y^{5}}$ $\newline$ Answer:

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Find indefinite integrals using the substitution

Full solution

Q. Assuming

x

and

y

are both positive, write the following expression in simplest radical form.

\newline

2 \sqrt{25 x^{6} y^{5}}

\newline

Answer:

Simplify Product Inside Radical: We start by simplifying the square root of the product inside the radical. We know that the square root of a product is the product of the square roots, and we can also simplify the square root of a perfect square. $\newline$ $2\sqrt{25x^{6}y^{5}} = 2\sqrt{25} \times \sqrt{x^{6}} \times \sqrt{y^{5}}$
Simplify Square Roots: Next, we simplify each square root separately. The square root of $25$ is $5$ , the square root of $x^6$ is $x^3$ because $(x^3)^2 = x^6$ , and the square root of $y^5$ is $y^2 \sqrt{y}$ because $(y^2)^2 \cdot y = y^5$ . $\newline$ $2 \cdot 5 \cdot x^3 \cdot y^2 \cdot \sqrt{y}$
Multiply Constants and Like Terms: Now we multiply the constants and the like terms together. $2 \times 5 = 10$ $10 \times x^3 \times y^2 \times \sqrt{y}$
Write in Simplest Form: Finally, we write the expression in its simplest radical form. $10x^3y^2\sqrt{y}$

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