Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What does the set \{x | x > -2 \text{ and } x \leq 5\} represent?\newlineChoices:\newline(A)all numbers less than −2-2 and greater than 55 \newline(B)all numbers greater than −2-2 and less than or equal to 55 \newline(C)all numbers less than −2-2 and greater than or equal to 55 \newline(D)all numbers greater than or equal to −2-2 and less than or equal to 55

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Set-builder notationright chevron icon

Full solution

Q. What does the set {x∣x>−2 and x≤5}\{x | x > -2 \text{ and } x \leq 5\} represent?\newlineChoices:\newline(A)all numbers less than −2-2 and greater than 55 \newline(B)all numbers greater than −2-2 and less than or equal to 55 \newline(C)all numbers less than −2-2 and greater than or equal to 55 \newline(D)all numbers greater than or equal to −2-2 and less than or equal to 55
  1. Understand set notation: Understand the set notation. The set {x | x > -2 \text{ and } x \leq 5} uses the inequality symbols '>' and '\leq' to describe the range of numbers that xx can be. The '>' symbol means 'greater than' and the '\leq' symbol means 'less than or equal to'.
  2. Interpret first condition: Interpret the first condition x > -2. This means that xx must be greater than −2-2, which includes all numbers that are just above −2-2 but not −2-2 itself.
  3. Interpret second condition: Interpret the second condition x≤5x \leq 5. This means that xx must be less than or equal to 55, which includes all numbers up to and including 55.
  4. Combine conditions: Combine both conditions. Since xx must satisfy both conditions simultaneously, xx must be a number that is greater than −2-2 and at the same time less than or equal to 55. This means xx can be any number between −2-2 (not including −2-2) and 55 (including 55).
  5. Match to given choices: Match the combined condition to the given choices. The set of numbers that are greater than −2-2 and less than or equal to 55 corresponds to choice (B) all numbers greater than −2-2 and less than or equal to 55.

More problems from Set-builder notation

Question
z=−24−12.7i z=-24-12.7 i \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=−24 and Im⁡(z)=−12.7 \begin{array}{l} \operatorname{Re}(z)=-24 \text { and } \\ \operatorname{Im}(z)=-12.7 \end{array} \newline(B)\newlineRe⁡(z)=−24 and Im⁡(z)=−12.7i \begin{array}{l} \operatorname{Re}(z)=-24 \text { and } \\ \operatorname{Im}(z)=-12.7 i \end{array} \newline(C)\newlineRe⁡(z)=−12.7 and Im⁡(z)=−24 \begin{array}{l} \operatorname{Re}(z)=-12.7 \text { and } \\ \operatorname{Im}(z)=-24 \end{array} \newline(D)\newlineRe⁡(z)=−12.7i and Im⁡(z)=−24 \begin{array}{l} \operatorname{Re}(z)=-12.7 i \text { and } \\ \operatorname{Im}(z)=-24 \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
z=77−27.8i z=77-27.8 i \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=77 and Im⁡(z)=−27.8 \begin{array}{l} \operatorname{Re}(z)=77 \text { and } \\ \operatorname{Im}(z)=-27.8 \end{array} \newline(B)\newlineRe⁡(z)=−27.8i and Im⁡(z)=77 \begin{array}{l} \operatorname{Re}(z)=-27.8 i \text { and } \\ \operatorname{Im}(z)=77 \end{array} \newline(C)\newlineRe⁡(z)=−27.8 and Im⁡(z)=77 \begin{array}{l} \operatorname{Re}(z)=-27.8 \text { and } \\ \operatorname{Im}(z)=77 \end{array} \newline(D)\newlineRe⁡(z)=77 and Im⁡(z)=−27.8i \begin{array}{l} \operatorname{Re}(z)=77 \text { and } \\ \operatorname{Im}(z)=-27.8 i \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
z=−16i−92.3 z=-16 i-92.3 \newlineWhat are the real and imaginary parts of z z ?\newlineChoose 11 answer:\newline(A)\newlineRe⁡(z)=−92.3 and Im⁡(z)=−16i \begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 i \end{array} \newline(B)\newlineRe⁡(z)=−92.3 and Im⁡(z)=−16 \begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 \end{array} \newline(C)\newlineRe⁡(z)=−16i and Im⁡(z)=−92.3 \begin{array}{l} \operatorname{Re}(z)=-16 i \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array} \newline(D)\newlineRe⁡(z)=−16 and Im⁡(z)=−92.3 \begin{array}{l} \operatorname{Re}(z)=-16 \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
x2+8x+6=0 x^{2}+8 x+6=0 \newlineWhat are the solutions to the given equation?\newlineChoose 11 answer:\newline(A)\newlinex=−8−10 and x=−8+10 \begin{array}{l} x=-8-\sqrt{10} \text { and } \\ x=-8+\sqrt{10} \end{array} \newline(B)\newlinex=−8−7 and x=−8+7 \begin{array}{l} x=-8-\sqrt{7} \text { and } \\ x=-8+\sqrt{7} \end{array} \newline(C)\newlinex=−4−10 and x=−4+10 \begin{array}{l} x=-4-\sqrt{10} \text { and } \\ x=-4+\sqrt{10} \end{array} \newline(D)\newlinex=−4−7 and x=−4+7 \begin{array}{l} x=-4-\sqrt{7} \text { and } \\ x=-4+\sqrt{7} \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
If x2+6x−5=0 x^{2}+6 x-5=0 , what are the values of x x ?\newlineChoose 11 answer:\newline(A) −3−14 -3-\sqrt{14} and −3+14 -3+\sqrt{14} \newline(B) 3−14 3-\sqrt{14} and 3+14 3+\sqrt{14} \newline(C) −1-1 and −5-5\newline(D) 11 and 55
Get tutor helpright-arrow

Posted 10 months ago

Question
Consider the expression 4(8x+5) 4(8 x+5) .\newlineComplete 22 descriptions of the parts of the expression.\newline11. The entire expression is the product of □\square. \newline22. On its own, (8x+5) (8 x+5) is a sum with □\square.
Get tutor helpright-arrow

Posted 10 months ago

Question
E=[−1−2−2−1] E=\left[\begin{array}{ll}-1 & -2 \\ -2 & -1\end{array}\right] and A=[202−1]. A=\left[\begin{array}{rr} 2 & 0 \\ 2 & -1 \end{array}\right] . \newlineLet H=EA \mathrm{H}=\mathrm{EA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 9 months ago

Question
B=[5−2−15] \mathbf{B}=\left[\begin{array}{rr}5 & -2 \\ -1 & 5\end{array}\right] and A=[2002] \mathrm{A}=\left[\begin{array}{ll}2 & 0 \\ 0 & 2\end{array}\right] .\newlineLet H=BA \mathrm{H}=\mathrm{BA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 9 months ago

Question
B=[0−12] \mathrm{B}=\left[\begin{array}{r}0 \\ -1 \\ 2\end{array}\right] and A=[12] \mathrm{A}=\left[\begin{array}{ll}1 & 2\end{array}\right] \newlineLet H=BA \mathrm{H}=\mathrm{BA} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 9 months ago

Question
E=[52−2] and D=[53] \mathrm{E}=\left[\begin{array}{r} 5 \\ 2 \\ -2 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{ll} 5 & 3 \end{array}\right] \newlineLet H=ED \mathrm{H}=\mathrm{ED} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
Get tutor helpright-arrow

Posted 9 months ago

View all (8)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant