z=-16 i-92.3 What are the real and imaginary parts of z ? Choose 1 answer: (A) {:[Re(z)=-92.3" and "],[Im(z)=-16 i]:} (B) {:[Re(z)=-92.3" and "],[Im(z)=-16]:} (c) {:[Re(z)=-16 i" and "],[Im(z)=-92.3]:} (D) {:[Re(z)=-16" and "],[Im(z)=-92.3]:}

Identifying real and imaginary parts: Let's identify the real and imaginary parts of the complex number z = -16 i - 92.3. A complex number is generally written in the form z = a + bi, where a is the real part and bi is the imaginary part.Finding the real part: The real part of the complex number z is the term without the imaginary unit i, which is -92.3. So, Re(z) = -92.3.Finding the imaginary part: The imaginary part of the complex number z is the term with the imaginary unit i, which is -16i. However, when we refer to the imaginary part, we only take the coefficient of i, which is -16. So, Im(z) = -16.

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z=-16 i-92.3
What are the real and imaginary parts of
z ?
Choose 1 answer:
(A)

{:[Re(z)=-92.3" and "],[Im(z)=-16 i]:}
(B)

{:[Re(z)=-92.3" and "],[Im(z)=-16]:}
(c)

{:[Re(z)=-16 i" and "],[Im(z)=-92.3]:}
(D)

{:[Re(z)=-16" and "],[Im(z)=-92.3]:}

$z=-16 i-92.3$ $\newline$ What are the real and imaginary parts of $z$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $\newline$ $\begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 i \end{array}$ $\newline$ (B) $\newline$ $\begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 \end{array}$ $\newline$ (C) $\newline$ $\begin{array}{l} \operatorname{Re}(z)=-16 i \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}$ $\newline$ (D) $\newline$ $\begin{array}{l} \operatorname{Re}(z)=-16 \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}$

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Full solution

z=-16 i-92.3

\newline

What are the real and imaginary parts of

z

\newline

Choose

1

answer:

\newline

(A)

\newline

\begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 i \end{array}

\newline

(B)

\newline

\begin{array}{l} \operatorname{Re}(z)=-92.3 \text { and } \\ \operatorname{Im}(z)=-16 \end{array}

\newline

(C)

\newline

\begin{array}{l} \operatorname{Re}(z)=-16 i \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}

\newline

(D)

\newline

\begin{array}{l} \operatorname{Re}(z)=-16 \text { and } \\ \operatorname{Im}(z)=-92.3 \end{array}

Identifying real and imaginary parts: Let's identify the real and imaginary parts of the complex number $z = -16i - 92.3$ . A complex number is generally written in the form $z = a + bi$ , where $a$ is the real part and $bi$ is the imaginary part.
Finding the real part: The real part of the complex number $z$ is the term without the imaginary unit $i$ , which is $-92.3$ . So, $\text{Re}(z) = -92.3$ .
Finding the imaginary part: The imaginary part of the complex number $z$ is the term with the imaginary unit $i$ , which is $-16i$ . However, when we refer to the imaginary part, we only take the coefficient of $i$ , which is $-16$ . So, $\text{Im}(z) = -16$ .