E=[[5],[2],[-2]]" and "D=[[5,3]] Let H=ED. Find H. H=[]

Understand matrix multiplication: Understand matrix multiplication. Matrix multiplication involves taking the rows of the first matrix (E) and multiplying them by the columns of the second matrix (D), then summing the products to get the entries of the resulting matrix (H).Identify matrix dimensions: Identify the dimensions of the matrices. Matrix E has dimensions 3x1 (3 rows and 1 column), and matrix D has dimensions 1x2 (1 row and 2 columns). The resulting matrix H will have dimensions that are the product of the number of rows of E and the number of columns of D, which is 3x2.Perform matrix multiplication: Perform the matrix multiplication. We multiply each element of the rows of E by the corresponding elements of the columns of D and sum the products to get the entries of H. H = [[5 * 5 + (not applicable, as there is only one element in the row and column)], [2 * 5 + (not applicable, as there is only one element in the row and column)], [-2 * 5 + (not applicable, as there is only one element in the row and column)]] This simplifies to: H = [[25], [10], [-10]]

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

E=[[5],[2],[-2]]" and "D=[[5,3]]
Let
H=ED. Find
H.

H=[]

$\mathrm{E}=\left[\begin{array}{r} 5 \\ 2 \\ -2 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{ll} 5 & 3 \end{array}\right]$ $\newline$ Let $\mathrm{H}=\mathrm{ED}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

View step-by-step help

Home

Math Problems

Algebra 1

Unions and intersections of sets

Full solution

\mathrm{E}=\left[\begin{array}{r} 5 \\ 2 \\ -2 \end{array}\right] \text { and } \mathrm{D}=\left[\begin{array}{ll} 5 & 3 \end{array}\right]

\newline

Let

\mathrm{H}=\mathrm{ED}

. Find

\mathrm{H}

\newline

\mathbf{H}=

Understand matrix multiplication: Understand matrix multiplication. Matrix multiplication involves taking the rows of the first matrix $E$ and multiplying them by the columns of the second matrix $D$ , then summing the products to get the entries of the resulting matrix $H$ .
Identify matrix dimensions: Identify the dimensions of the matrices. $\newline$ Matrix $E$ has dimensions $3 \times 1$ ( $3$ rows and $1$ column), and matrix $D$ has dimensions $1 \times 2$ ( $1$ row and $2$ columns). The resulting matrix $H$ will have dimensions that are the product of the number of rows of $E$ and the number of columns of $D$ , which is $3 \times 1$ $1$ .
Perform matrix multiplication: Perform the matrix multiplication. $\newline$ We multiply each element of the rows of $E$ by the corresponding elements of the columns of $D$ and sum the products to get the entries of $H$ . $\newline$ $H = \left[\begin{array}{c} 5 \times 5 + (\text{not applicable, as there is only one element in the row and column}), \ 2 \times 5 + (\text{not applicable, as there is only one element in the row and column}), \ -2 \times 5 + (\text{not applicable, as there is only one element in the row and column}) \end{array}\right]$ $\newline$ This simplifies to: $\newline$ $H = \left[\begin{array}{c} 25, \ 10, \ -10 \end{array}\right]$