E=[[-1,-2],[-2,-1]] and A=[[2,0],[2,-1]] Let H=EA. Find H. H=[◻

Define Matrices E and A: Define the matrices E and A. Matrix E is given by E = [[-1, -2], [-2, -1]] and matrix A is given by A = [[2, 0], [2, -1]].Multiply Row 1 by Column 1: Multiply the first row of E by the first column of A. To find the element at the first row and first column of matrix H, we calculate (-1*2) + (-2*2) = -2 - 4 = -6.Multiply Row 1 by Column 2: Multiply the first row of E by the second column of A. To find the element at the first row and second column of matrix H, we calculate (-1*0) + (-2*-1) = 0 + 2 = 2.Multiply Row 2 by Column 1: Multiply the second row of E by the first column of A. To find the element at the second row and first column of matrix H, we calculate (-2*2) + (-1*2) = -4 - 2 = -6.Multiply Row 2 by Column 2: Multiply the second row of E by the second column of A. To find the element at the second row and second column of matrix H, we calculate (-2*0) + (-1*-1) = 0 + 1 = 1.

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E=[[-1,-2],[-2,-1]] and

A=[[2,0],[2,-1]]
Let
H=EA. Find
H.

H=[◻

$E=\left[\begin{array}{ll}-1 & -2 \\ -2 & -1\end{array}\right]$ and $A=\left[\begin{array}{rr} 2 & 0 \\ 2 & -1 \end{array}\right] .$ $\newline$ Let $\mathrm{H}=\mathrm{EA}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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Math Problems

Algebra 1

Unions and intersections of sets

Full solution

E=\left[\begin{array}{ll}-1 & -2 \\ -2 & -1\end{array}\right]

and

A=\left[\begin{array}{rr} 2 & 0 \\ 2 & -1 \end{array}\right] .

\newline

Let

\mathrm{H}=\mathrm{EA}

. Find

\mathrm{H}

\newline

\mathbf{H}=

Define Matrices E and A: Define the matrices E and A. Matrix E is given by $E = \begin{bmatrix} -1 & -2 \ -2 & -1 \end{bmatrix}$ and matrix A is given by $A = \begin{bmatrix} 2 & 0 \ 2 & -1 \end{bmatrix}$ .
Multiply Row $1$ by Column $1$ : Multiply the first row of $E$ by the first column of $A$ . To find the element at the first row and first column of matrix $H$ , we calculate $(-1 \times 2) + (-2 \times 2) = -2 - 4 = -6$ .
Multiply Row $1$ by Column $2$ : Multiply the first row of $E$ by the second column of $A$ . To find the element at the first row and second column of matrix $H$ , we calculate $(-1 \times 0) + (-2 \times -1) = 0 + 2 = 2$ .
Multiply Row $2$ by Column $1$ : Multiply the second row of $E$ by the first column of $A$ . To find the element at the second row and first column of matrix $H$ , we calculate $(-2 \times 2) + (-1 \times 2) = -4 - 2 = -6$ .
Multiply Row $2$ by Column $2$ : Multiply the second row of $E$ by the second column of $A$ . To find the element at the second row and second column of matrix $H$ , we calculate $(-2 \times 0) + (-1 \times -1) = 0 + 1 = 1$ .