B=[[5,-2],[-1,5]] and A=[[2,0],[0,2]] Let H=BA. Find H. H=[quad]

Understand matrix multiplication: Understand matrix multiplication. To multiply two matrices, we take the dot product of the rows of the first matrix with the columns of the second matrix. The resulting matrix will have the same number of rows as the first matrix and the same number of columns as the second matrix.Write down given matrices: Write down the given matrices. Matrix B is given as B=[[5,-2],[-1,5]] and matrix A is given as A=[[2,0],[0,2]].Multiply first row: Multiply the first row of B by the first column of A. The first row of B is [5, -2] and the first column of A is [2, 0]. The dot product is (5*2) + (-2*0) = 10 + 0 = 10.Multiply second row: Multiply the first row of B by the second column of A. The first row of B is [5, -2] and the second column of A is [0, 2]. The dot product is (5*0) + (-2*2) = 0 - 4 = -4.Combine results: Multiply the second row of B by the first column of A. The second row of B is [-1, 5] and the first column of A is [2, 0]. The dot product is (-1*2) + (5*0) = -2 + 0 = -2.Multiply the second row of B by the second column of A. The second row of B is [-1, 5] and the second column of A is [0, 2]. The dot product is (-1*0) + (5*2) = 0 + 10 = 10.Combine the results to form the matrix H. The results from steps 3 to 6 give us the matrix H: H = [[10, -4], [-2, 10]]

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B=[[5,-2],[-1,5]] and
A=[[2,0],[0,2]]
Let
H=BA. Find
H.

H=[quad]

$\mathbf{B}=\left[\begin{array}{rr}5 & -2 \\ -1 & 5\end{array}\right]$ and $\mathrm{A}=\left[\begin{array}{ll}2 & 0 \\ 0 & 2\end{array}\right]$ . $\newline$ Let $\mathrm{H}=\mathrm{BA}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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Math Problems

Algebra 1

Unions and intersections of sets

Full solution

\mathbf{B}=\left[\begin{array}{rr}5 & -2 \\ -1 & 5\end{array}\right]

and

\mathrm{A}=\left[\begin{array}{ll}2 & 0 \\ 0 & 2\end{array}\right]

\newline

Let

\mathrm{H}=\mathrm{BA}

. Find

\mathrm{H}

\newline

\mathbf{H}=

Understand matrix multiplication: Understand matrix multiplication. To multiply two matrices, we take the dot product of the rows of the first matrix with the columns of the second matrix. The resulting matrix will have the same number of rows as the first matrix and the same number of columns as the second matrix.
Write down given matrices: Write down the given matrices. Matrix $B$ is given as $B=\left[\begin{array}{cc}5 & -2 \ -1 & 5\end{array}\right]$ and matrix $A$ is given as $A=\left[\begin{array}{cc}2 & 0 \ 0 & 2\end{array}\right]$ .
Multiply first row: Multiply the first row of $B$ by the first column of $A$ . The first row of $B$ is $[5, -2]$ and the first column of $A$ is $[2, 0]$ . The dot product is $(5 \times 2) + (-2 \times 0) = 10 + 0 = 10$ .
Multiply second row: Multiply the first row of $B$ by the second column of $A$ . The first row of $B$ is $[5, -2]$ and the second column of $A$ is $[0, 2]$ . The dot product is $(5\times0) + (-2\times2) = 0 - 4 = -4$ .
Combine results: Multiply the second row of $B$ by the first column of $A$ . The second row of $B$ is $[-1, 5]$ and the first column of $A$ is $[2, 0]$ . The dot product is $(-1 \times 2) + (5 \times 0) = -2 + 0 = -2$ .
Combine results: Multiply the second row of $B$ by the first column of $A$ . The second row of $B$ is $[-1, 5]$ and the first column of $A$ is $[2, 0]$ . The dot product is $(-1\times2) + (5\times0) = -2 + 0 = -2$ .Multiply the second row of $B$ by the second column of $A$ . The second row of $B$ is $[-1, 5]$ and the second column of $A$ is $A$ $2$ . The dot product is $A$ $3$ .
Combine results: Multiply the second row of $B$ by the first column of $A$ . The second row of $B$ is $[-1, 5]$ and the first column of $A$ is $[2, 0]$ . The dot product is $(-1\times2) + (5\times0) = -2 + 0 = -2$ . Multiply the second row of $B$ by the second column of $A$ . The second row of $B$ is $[-1, 5]$ and the second column of $A$ is $A$ $2$ . The dot product is $A$ $3$ . Combine the results to form the matrix $A$ $4$ . The results from steps $3$ to $6$ give us the matrix $A$ $4$ : $A$ $6$