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Use the given information to find the unknown value: 
y varies directly as the cube of 
x. When 
x=2, then 
y=16. Find 
y when 
x=3.

Use the given information to find the unknown value: y y varies directly as the cube of x x . When x=2 x=2 , then y=16 y=16 . Find y y when x=3 x=3 .

Full solution

Q. Use the given information to find the unknown value: y y varies directly as the cube of x x . When x=2 x=2 , then y=16 y=16 . Find y y when x=3 x=3 .
  1. Establish Relationship: Establish the direct variation relationship between yy and the cube of xx. Since yy varies directly as the cube of xx, we can write the equation as y=kx3y = kx^3, where kk is the constant of proportionality.
  2. Find Constant of Proportionality: Use the given values to find the constant of proportionality kk. We know that y=16y = 16 when x=2x = 2. Substitute these values into the equation y=kx3y = kx^3 to find kk. 16=k×2316 = k \times 2^3 16=k×816 = k \times 8
  3. Solve for k: Solve for k.\newlineDivide both sides by 88 to isolate k.\newlinek=168k = \frac{16}{8}\newlinek=2k = 2
  4. Write Equation with kk: Write the direct variation equation with the found value of kk. Now that we know k=2k = 2, we can write the equation as y=2x3y = 2x^3.
  5. Find yy for x=3x=3: Find yy when x=3x = 3 using the direct variation equation.\newlineSubstitute x=3x = 3 into the equation y=2x3y = 2x^3 to find yy.\newliney=2×33y = 2 \times 3^3\newliney=2×27y = 2 \times 27\newliney=54y = 54

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