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If 
a_(1)=9 and 
a_(n+1)=2a_(n)+2 then find the value of 
a_(5).
Answer:

If a1=9 a_{1}=9 and an+1=2an+2 a_{n+1}=2 a_{n}+2 then find the value of a5 a_{5} .\newlineAnswer:

Full solution

Q. If a1=9 a_{1}=9 and an+1=2an+2 a_{n+1}=2 a_{n}+2 then find the value of a5 a_{5} .\newlineAnswer:
  1. Identify Given Sequence: Identify the given sequence and the recursive formula.\newlineWe are given the first term of the sequence, a1=9a_{1} = 9, and the recursive formula an+1=2an+2a_{n+1} = 2a_{n} + 2, which tells us how to find any term in the sequence based on the previous term.
  2. Find a2a_{2}: Use the recursive formula to find a2a_{2}. We know a1=9a_{1} = 9, so we can find a2a_{2} by plugging a1a_{1} into the recursive formula: a2=2a1+2a_{2} = 2a_{1} + 2 a2=2×9+2a_{2} = 2 \times 9 + 2 a2=18+2a_{2} = 18 + 2 a2=20a_{2} = 20
  3. Find a3a_{3}: Use the recursive formula to find a3a_{3}. Now that we have a2a_{2}, we can find a3a_{3}: a3=2a2+2a_{3} = 2a_{2} + 2 a3=2×20+2a_{3} = 2 \times 20 + 2 a3=40+2a_{3} = 40 + 2 a3=42a_{3} = 42
  4. Find a4a_{4}: Use the recursive formula to find a4a_{4}. With a3a_{3} found, we can find a4a_{4}: a4=2a3+2a_{4} = 2a_{3} + 2 a4=2×42+2a_{4} = 2 \times 42 + 2 a4=84+2a_{4} = 84 + 2 a4=86a_{4} = 86
  5. Find a5a_{5}: Use the recursive formula to find a5a_{5}. Finally, we use a4a_{4} to find a5a_{5}: a5=2a4+2a_{5} = 2a_{4} + 2 a5=2×86+2a_{5} = 2 \times 86 + 2 a5=172+2a_{5} = 172 + 2 a5=174a_{5} = 174

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