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Let’s check out your problem:
Use the following function rule to find
f
(
6
)
f(6)
f
(
6
)
.
\newline
f
(
x
)
=
8
x
+
x
2
f(x) = 8x + x^2
f
(
x
)
=
8
x
+
x
2
\newline
f
(
6
)
=
f(6) =
f
(
6
)
=
_____
View step-by-step help
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Math Problems
Grade 8
Evaluate a nonlinear function
Full solution
Q.
Use the following function rule to find
f
(
6
)
f(6)
f
(
6
)
.
\newline
f
(
x
)
=
8
x
+
x
2
f(x) = 8x + x^2
f
(
x
)
=
8
x
+
x
2
\newline
f
(
6
)
=
f(6) =
f
(
6
)
=
_____
Substitute
x
=
6
x = 6
x
=
6
:
Substitute
x
=
6
x = 6
x
=
6
into the function rule.
f
(
6
)
=
8
(
6
)
+
6
2
f(6) = 8(6) + 6^2
f
(
6
)
=
8
(
6
)
+
6
2
Calculate values:
Calculate the values.
8
(
6
)
=
48
8(6) = 48
8
(
6
)
=
48
and
6
2
=
36
6^2 = 36
6
2
=
36
Add results:
Add the results from Step
2
2
2
.
\newline
f
(
6
)
=
48
+
36
=
84
f(6) = 48 + 36 = 84
f
(
6
)
=
48
+
36
=
84
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3
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2
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Question
If
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5
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5
−
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y
2
=
0
then find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
at the point
(
4
,
5
)
(4,5)
(
4
,
5
)
.
\newline
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=
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Question
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(
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y
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∣
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Question
If
y
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y
then find
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d
x
d
y
at the point
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3
)
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(
−
1
,
3
)
.
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∣
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Question
If
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4
x
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4
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4
x
2
=
y
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−
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3
then find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
at the point
(
1
,
2
)
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(
1
,
2
)
.
\newline
Answer:
d
y
d
x
∣
(
1
,
2
)
=
\left.\frac{d y}{d x}\right|_{(1,2)}=
d
x
d
y
∣
∣
(
1
,
2
)
=
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Question
If
0
=
4
+
5
x
3
−
y
2
0=4+5 x^{3}-y^{2}
0
=
4
+
5
x
3
−
y
2
then find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
at the point
(
1
,
−
3
)
(1,-3)
(
1
,
−
3
)
.
\newline
Answer:
d
y
d
x
∣
(
1
,
−
3
)
=
\left.\frac{d y}{d x}\right|_{(1,-3)}=
d
x
d
y
∣
∣
(
1
,
−
3
)
=
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Question
If
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y
3
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2
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y
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−
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2
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then find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
at the point
(
4
,
−
2
)
(4,-2)
(
4
,
−
2
)
.
\newline
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d
y
d
x
∣
(
4
,
−
2
)
=
\left.\frac{d y}{d x}\right|_{(4,-2)}=
d
x
d
y
∣
∣
(
4
,
−
2
)
=
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Question
Given
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=
−
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x
)
y=-2 \sin (2 x)
y
=
−
2
sin
(
2
x
)
, find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
.
\newline
Answer:
d
y
d
x
=
\frac{d y}{d x}=
d
x
d
y
=
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