Solve for z. 6z - 2 = 6 + 10z z = ____

Move z terms left: First, we want to get all the terms with z on one side of the equation and the constants on the other side. To do this, we can subtract 10z from both sides of the equation to move the z terms to the left side. Calculation: 6z - 2 - 10z = 6 + 10z - 10zSimplify equation: After performing the subtraction, we simplify the equation. Calculation: -4z - 2 = 6Isolate z term: Next, we want to isolate the term with z by moving the constant term on the left side to the right side. We do this by adding 2 to both sides of the equation. Calculation: -4z - 2 + 2 = 6 + 2Simplify after adding: Simplifying the equation after adding 2 to both sides gives us: Calculation: -4z = 8Divide by -4: To solve for z, we need to divide both sides of the equation by -4. Calculation: z = 8 / -4Find value of z: Finally, we perform the division to find the value of z. Calculation: z = -2

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Solve for $z$ . $\newline$ $6z - 2 = 6 + 10z$ $\newline$ $z =$ __

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Algebra 2

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Q. Solve for

z

\newline

6z - 2 = 6 + 10z

\newline

z =

Move z terms left: First, we want to get all the terms with $z$ on one side of the equation and the constants on the other side. To do this, we can subtract $10z$ from both sides of the equation to move the $z$ terms to the left side. $\newline$ Calculation: $6z - 2 - 10z = 6 + 10z - 10z$
Simplify equation: After performing the subtraction, we simplify the equation. $\newline$ Calculation: $-4z - 2 = 6$
Isolate z term: Next, we want to isolate the term with $z$ by moving the constant term on the left side to the right side. We do this by adding $2$ to both sides of the equation. $\newline$ Calculation: $-4z - 2 + 2 = 6 + 2$
Simplify after adding: Simplifying the equation after adding $2$ to both sides gives us: $\newline$ Calculation: $-4z = 8$
Divide by $-4$ : To solve for $z$ , we need to divide both sides of the equation by $-4$ . $\newline$ Calculation: $z = \frac{8}{-4}$
Find value of z: Finally, we perform the division to find the value of $z$ . $\newline$ Calculation: $z = -2$