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Find the value of 
x that solves the equation 
ln(x+3)-ln 2=0.
Answer:

Find the value of x x that solves the equation ln(x+3)ln2=0 \ln (x+3)-\ln 2=0 .\newlineAnswer:

Full solution

Q. Find the value of x x that solves the equation ln(x+3)ln2=0 \ln (x+3)-\ln 2=0 .\newlineAnswer:
  1. Combine logarithms: We are given the equation ln(x+3)ln(2)=0\ln(x+3) - \ln(2) = 0. To solve for xx, we will first combine the logarithms on the left side using the property of logarithms that ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right).
  2. Use logarithmic property: Combining the logarithms, we get ln(x+32)=0\ln\left(\frac{x+3}{2}\right) = 0. Now, we can use the property that ln(a)=0\ln(a) = 0 implies a=1a = 1 to find the value inside the logarithm that makes the equation true.
  3. Set inside equal to 11: Setting the inside of the logarithm equal to 11, we have \frac{x+33}{22} = 11. Now we can solve for x by multiplying both sides of the equation by 22.
  4. Multiply both sides: Multiplying both sides by 22, we get x+3=2×1x+3 = 2 \times 1, which simplifies to x+3=2x+3 = 2.
  5. Isolate variable: To isolate xx, we subtract 33 from both sides of the equation, giving us x=23x = 2 - 3.
  6. Final solution: Subtracting 33 from 22, we find that x=1x = -1.

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