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Find the value of 
x that solves the equation 
ln(x-3)=1+ln 2.
Answer:

Find the value of x x that solves the equation ln(x3)=1+ln2 \ln (x-3)=1+\ln 2 .\newlineAnswer:

Full solution

Q. Find the value of x x that solves the equation ln(x3)=1+ln2 \ln (x-3)=1+\ln 2 .\newlineAnswer:
  1. Combine Logarithmic Terms: We are given the equation ln(x3)=1+ln2\ln(x-3) = 1 + \ln 2. To solve for xx, we need to isolate xx on one side of the equation. First, we can use the property of logarithms that allows us to combine the terms on the right side of the equation.
  2. Rewrite Using Logarithmic Property: We know that lna+lnb=ln(ab)\ln a + \ln b = \ln(ab). So we can rewrite the right side of the equation as ln(2e)\ln(2e), where ee is the base of the natural logarithm and is approximately equal to 2.718282.71828.\newlineln(x3)=ln(2e)\ln(x-3) = \ln(2e)
  3. Equate Arguments of Logarithms: Since the natural logarithm function ln\ln is a one-to-one function, if ln(a)=ln(b)\ln(a) = \ln(b), then a=ba = b. Therefore, we can equate the arguments of the logarithms from both sides of the equation.x3=2ex - 3 = 2e
  4. Solve for x: Now, we solve for x by adding 33 to both sides of the equation.\newlinex=2e+3x = 2e + 3
  5. Substitute and Calculate: We substitute the approximate value of ee into the equation to find the numerical value of xx.\newlinex2(2.71828)+3x \approx 2(2.71828) + 3\newlinex5.43656+3x \approx 5.43656 + 3\newline$x \approx \(8\).\(43656\)

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