Move x terms: We have the equation 6x + 32 = 8x - 8. To solve for x, we need to get all the x terms on one side and the constant terms on the other side. Let's start by moving the x terms to the left side by subtracting 8x from both sides of the equation. 6x + 32 - 8x = 8x - 8 - 8xSimplify equation: Simplify the equation by combining like terms. 6x - 8x + 32 = -8 -2x + 32 = -8Isolate variable term: Now, we need to isolate the variable term -2x. We can do this by subtracting 32 from both sides of the equation. -2x + 32 - 32 = -8 - 32 -2x = -40Divide to solve for x: To solve for x, we need to divide both sides of the equation by -2. (-2x) / -2 = (-40) / -2 x = 20

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Find the value of `x` $\newline$ $6x+32=8x-8$

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Algebra 2

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Q. Find the value of `x`

\newline

6x+32=8x-8

Move x terms: We have the equation $6x + 32 = 8x - 8$ . To solve for x, we need to get all the x terms on one side and the constant terms on the other side. Let's start by moving the x terms to the left side by subtracting $8x$ from both sides of the equation. $\newline$ $6x + 32 - 8x = 8x - 8 - 8x$
Simplify equation: Simplify the equation by combining like terms. $\newline$ $6x - 8x + 32 = -8$ $\newline$ $-2x + 32 = -8$
Isolate variable term: Now, we need to isolate the variable term $-2x$ . We can do this by subtracting $32$ from both sides of the equation. $\newline$ $-2x + 32 - 32 = -8 - 32$ $\newline$ $-2x = -40$
Divide to solve for $x$ : To solve for $x$ , we need to divide both sides of the equation by $-2$ . $\frac{-2x}{-2} = \frac{-40}{-2}$ $x = 20$