Solve for t. 7 + 4t = 5t + 17 t = ____

Move 4t to right: We have the equation 7 + 4t = 5t + 17. To solve for t, we need to get all the terms with t on one side and the constant terms on the other side. Let's start by moving the 4t term to the right side by subtracting 4t from both sides of the equation. 7 + 4t - 4t = 5t + 17 - 4t 7 = t + 17Isolate t: Now, we have 7 = t + 17. Next, we need to isolate t by moving the constant term 17 to the left side. We do this by subtracting 17 from both sides of the equation. 7 - 17 = t + 17 - 17 -10 = tFinal solution: We have found the value of t. There is no need for further steps as we have isolated t and found its value.

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Solve for $t$ . $\newline$ $7 + 4t = 5t + 17$ $\newline$ $t =$ ____

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Algebra 2

Solve linear equations

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Q. Solve for

t

\newline

7 + 4t = 5t + 17

\newline

t =

____

Move $4t$ to right: We have the equation $7 + 4t = 5t + 17$ . To solve for $t$ , we need to get all the terms with $t$ on one side and the constant terms on the other side. Let's start by moving the $4t$ term to the right side by subtracting $4t$ from both sides of the equation. $\newline$ $7 + 4t - 4t = 5t + 17 - 4t$ $\newline$ $7 = t + 17$
Isolate t: Now, we have $7 = t + 17$ . Next, we need to isolate $t$ by moving the constant term $17$ to the left side. We do this by subtracting $17$ from both sides of the equation. $\newline$ $7 - 17 = t + 17 - 17$ $\newline$ $-10 = t$
Final solution: We have found the value of $t$ . There is no need for further steps as we have isolated $t$ and found its value.