Solve for b. 49=16+(3)/(7)b Answer: b=

Subtract to isolate b: We have the equation 49 = 16 + (3/7)b. To isolate b, we should first subtract 16 from both sides of the equation. Calculation: 49 - 16 = 16 + (3/7)b - 16 33 = (3/7)bMultiply by reciprocal to solve: Now we have 33 = (3/7)b. To solve for b, we need to multiply both sides by the reciprocal of (3/7), which is (7/3). Calculation: 33 * (7/3) = (3/7)b * (7/3) 77 = b

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Solve for $b$ . $\newline$ $49=16+\frac{3}{7} b$ $\newline$ Answer: $b=$

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Algebra 2

Solve multi-variable equations

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Q. Solve for

b

\newline

49=16+\frac{3}{7} b

\newline

Answer:

b=

Subtract to isolate $b$ : We have the equation $49 = 16 + \left(\frac{3}{7}\right)b$ . To isolate $b$ , we should first subtract $16$ from both sides of the equation. $\newline$ Calculation: $49 - 16 = 16 + \left(\frac{3}{7}\right)b - 16$ $\newline$ $33 = \left(\frac{3}{7}\right)b$
Multiply by reciprocal to solve: Now we have $33 = \left(\frac{3}{7}\right)b$ . To solve for $b$ , we need to multiply both sides by the reciprocal of $\left(\frac{3}{7}\right)$ , which is $\left(\frac{7}{3}\right)$ . $\newline$ Calculation: $33 \times \left(\frac{7}{3}\right) = \left(\frac{3}{7}\right)b \times \left(\frac{7}{3}\right)$ $\newline$ $77 = b$