If f(1)=5,f(2)=1 and f(n)=3f(n-1)+f(n-2) then find the value of f(4). Answer:

Identify Given Information: Identify the given information and the recursive formula. We are given a recursive function f(n) = 3f(n-1) + f(n-2), with initial conditions f(1) = 5 and f(2) = 1. We need to find the value of f(4).Calculate f(3): Use the recursive formula to find f(3). We know f(1) and f(2), so we can calculate f(3) using the formula f(n) = 3f(n-1) + f(n-2). f(3) = 3f(2) + f(1) f(3) = 3(1) + 5 f(3) = 3 + 5 f(3) = 8Calculate f(4): Use the recursive formula to find f(4). Now that we have f(3) and f(2), we can calculate f(4) using the formula f(n) = 3f(n-1) + f(n-2). f(4) = 3f(3) + f(2) f(4) = 3(8) + 1 f(4) = 24 + 1 f(4) = 25

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If
f(1)=5,f(2)=1 and
f(n)=3f(n-1)+f(n-2) then find the value of
f(4).
Answer:

If $f(1)=5, f(2)=1$ and $f(n)=3 f(n-1)+f(n-2)$ then find the value of $f(4)$ . $\newline$ Answer:

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Math Problems

Grade 8

Write and solve direct variation equations

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Q. If

f(1)=5, f(2)=1

and

f(n)=3 f(n-1)+f(n-2)

then find the value of

f(4)

\newline

Answer:

Identify Given Information: Identify the given information and the recursive formula. $\newline$ We are given a recursive function $f(n) = 3f(n-1) + f(n-2)$ , with initial conditions $f(1) = 5$ and $f(2) = 1$ . We need to find the value of $f(4)$ .
Calculate $f(3)$ : Use the recursive formula to find $f(3)$ . We know $f(1)$ and $f(2)$ , so we can calculate $f(3)$ using the formula $f(n) = 3f(n-1) + f(n-2)$ . $f(3) = 3f(2) + f(1)$ $f(3) = 3(1) + 5$ $f(3) = 3 + 5$ $f(3) = 8$
Calculate $f(4)$ : Use the recursive formula to find $f(4)$ . Now that we have $f(3)$ and $f(2)$ , we can calculate $f(4)$ using the formula $f(n) = 3f(n-1) + f(n-2)$ . $f(4) = 3f(3) + f(2)$ $f(4) = 3(8) + 1$ $f(4) = 24 + 1$ $f(4) = 25$