Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

If 
a_(1)=4,a_(2)=1 and 
a_(n)=2a_(n-1)+3a_(n-2) then find the value of 
a_(4).
Answer:

If a1=4,a2=1 a_{1}=4, a_{2}=1 and an=2an1+3an2 a_{n}=2 a_{n-1}+3 a_{n-2} then find the value of a4 a_{4} .\newlineAnswer:

Full solution

Q. If a1=4,a2=1 a_{1}=4, a_{2}=1 and an=2an1+3an2 a_{n}=2 a_{n-1}+3 a_{n-2} then find the value of a4 a_{4} .\newlineAnswer:
  1. Understand Formula and Conditions: Understand the recursive formula and initial conditions.\newlineThe recursive formula given is an=2an1+3an2a_{n}=2a_{n-1}+3a_{n-2}. This means that each term in the sequence is generated by multiplying the previous term by 22 and the term before that by 33, then adding the results. We are given a1=4a_{1}=4 and a2=1a_{2}=1 as initial conditions.
  2. Find Third Term: Find the third term of the sequence using the recursive formula.\newlineTo find a3a_{3}, we use the formula with n=3n=3, which means we need a2a_{2} and a1a_{1}.\newlinea3=2a2+3a1a_{3} = 2a_{2} + 3a_{1}\newlinea3=2(1)+3(4)a_{3} = 2(1) + 3(4)\newlinea3=2+12a_{3} = 2 + 12\newlinea3=14a_{3} = 14
  3. Find Fourth Term: Find the fourth term of the sequence using the recursive formula.\newlineNow that we have a3a_{3}, we can find a4a_{4} using the formula with n=4n=4, which means we need a3a_{3} and a2a_{2}.\newlinea4=2a3+3a2a_{4} = 2a_{3} + 3a_{2}\newlinea4=2(14)+3(1)a_{4} = 2(14) + 3(1)\newlinea4=28+3a_{4} = 28 + 3\newlinea4=31a_{4} = 31

More problems from Write and solve direct variation equations