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If 
a_(1)=3,a_(2)=1 and 
a_(n)=3a_(n-1)-2a_(n-2) then find the value of 
a_(5).
Answer:

If a1=3,a2=1 a_{1}=3, a_{2}=1 and an=3an12an2 a_{n}=3 a_{n-1}-2 a_{n-2} then find the value of a5 a_{5} .\newlineAnswer:

Full solution

Q. If a1=3,a2=1 a_{1}=3, a_{2}=1 and an=3an12an2 a_{n}=3 a_{n-1}-2 a_{n-2} then find the value of a5 a_{5} .\newlineAnswer:
  1. Identify Given Terms and Formula: Identify the given terms of the sequence and the recursive formula.\newlineWe are given a1=3a_{1}=3, a2=1a_{2}=1, and the recursive formula an=3an12an2a_{n}=3a_{n-1}-2a_{n-2}.
  2. Find a3a_{3}: Use the recursive formula to find a3a_{3}.\newlinea3=3a22a1a_{3} = 3a_{2} - 2a_{1}\newlinea3=3(1)2(3)a_{3} = 3(1) - 2(3)\newlinea3=36a_{3} = 3 - 6\newlinea3=3a_{3} = -3
  3. Find a4a_{4}: Use the recursive formula to find a4a_{4}.
    a4=3a32a2a_{4} = 3a_{3} - 2a_{2}
    a4=3(3)2(1)a_{4} = 3(-3) - 2(1)
    a4=92a_{4} = -9 - 2
    a4=11a_{4} = -11
  4. Find a5a_{5}: Use the recursive formula to find a5a_{5}.
    a5=3a42a3a_{5} = 3a_{4} - 2a_{3}
    a5=3(11)2(3)a_{5} = 3(-11) - 2(-3)
    a5=33+6a_{5} = -33 + 6
    a5=27a_{5} = -27

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