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If 
a_(1)=2,a_(2)=0 and 
a_(n)=2a_(n-1)-3a_(n-2) then find the value of 
a_(5).
Answer:

If a1=2,a2=0 a_{1}=2, a_{2}=0 and an=2an13an2 a_{n}=2 a_{n-1}-3 a_{n-2} then find the value of a5 a_{5} .\newlineAnswer:

Full solution

Q. If a1=2,a2=0 a_{1}=2, a_{2}=0 and an=2an13an2 a_{n}=2 a_{n-1}-3 a_{n-2} then find the value of a5 a_{5} .\newlineAnswer:
  1. Identify Given Terms and Formula: Identify the given terms of the sequence and the recursive formula.\newlineWe are given a1=2a_{1}=2, a2=0a_{2}=0, and the recursive formula an=2an13an2a_{n}=2a_{n-1}-3a_{n-2}.
  2. Find a3a_{3}: Use the recursive formula to find a3a_{3}.a3=2a23a1a_{3} = 2a_{2} - 3a_{1}a3=2(0)3(2)a_{3} = 2(0) - 3(2)a3=06a_{3} = 0 - 6a3=6a_{3} = -6
  3. Find a4a_{4}: Use the recursive formula to find a4a_{4}. \newlinea4=2a33a2a_{4} = 2a_{3} - 3a_{2}\newlinea4=2(6)3(0)a_{4} = 2(-6) - 3(0)\newlinea4=120a_{4} = -12 - 0\newlinea4=12a_{4} = -12
  4. Find a5a_{5}: Use the recursive formula to find a5a_{5}.
    a5=2a43a3a_{5} = 2a_{4} - 3a_{3}
    a5=2(12)3(6)a_{5} = 2(-12) - 3(-6)
    a5=24+18a_{5} = -24 + 18
    a5=6a_{5} = -6

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