Given h(x)=-x+3, solve for x when h(x)=0. Answer:

Set Equation to 0: Set the function h(x) equal to 0. We are given h(x) = -x + 3 and need to find x when h(x) = 0. So, we set up the equation 0 = -x + 3.Solve for x: Solve for x. To find x, we need to isolate it on one side of the equation. We can do this by adding x to both sides and subtracting 3 from both sides. 0 + x = -x + x + 3 - 3 x = 3Check Solution: Check the solution. Substitute x back into the original function to verify that h(x) equals 0. h(x) = -x + 3 h(3) = -(3) + 3 h(3) = -3 + 3 h(3) = 0 The solution x = 3 makes h(x) equal to 0, so it is correct.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Given
h(x)=-x+3, solve for
x when
h(x)=0.
Answer:

Given $h(x)=-x+3$ , solve for $x$ when $h(x)=0$ . $\newline$ Answer:

View step-by-step help

Home

Math Problems

Grade 8

Write and solve direct variation equations

Full solution

Q. Given

h(x)=-x+3

, solve for

x

when

h(x)=0

\newline

Answer:

Set Equation to $0$ : Set the function $h(x)$ equal to $0$ . We are given $h(x) = -x + 3$ and need to find $x$ when $h(x) = 0$ . So, we set up the equation $0 = -x + 3$ .
Solve for x: Solve for x. $\newline$ To find $x$ , we need to isolate it on one side of the equation. $\newline$ We can do this by adding $x$ to both sides and subtracting $3$ from both sides. $\newline$ $0 + x = -x + x + 3 - 3$ $\newline$ $x = 3$
Check Solution: Check the solution. $\newline$ Substitute $x$ back into the original function to verify that $h(x)$ equals $0$ . $\newline$ $h(x) = -x + 3$ $\newline$ $h(3) = -(3) + 3$ $\newline$ $h(3) = -3 + 3$ $\newline$ $h(3) = 0$ $\newline$ The solution $x = 3$ makes $h(x)$ equal to $0$ , so it is correct.