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Does the point (−1,−5)(-1, -5) satisfy the equation y=2x2+6x−1y = 2x^2 + 6x - 1?\newlineChoices:\newline(A)yes\newline(B)no

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Is (x, y) a solution to the nonlinear equation?right chevron icon

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Q. Does the point (−1,−5)(-1, -5) satisfy the equation y=2x2+6x−1y = 2x^2 + 6x - 1?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute x-value: Substitute the xx-value from the point into the equation to find yy.y=2(−1)2+6(−1)−1y = 2(-1)^2 + 6(-1) - 1y=2(1)−6−1y = 2(1) - 6 - 1y=2−6−1y = 2 - 6 - 1y=−5y = -5
  2. Compare y-values: Compare the calculated yy-value with the yy-value from the point.\newlineCalculated y=−5y = -5, Point's y=−5y = -5\newlineSince both values are the same, the point satisfies the equation.

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