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Does (2,−1)(2, -1) make the equation y=x2−4x+−3y = x^2 - 4x + -3 true?\newlineChoices:\newline(A) yes\newline(B) no

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Is (x, y) a solution to the nonlinear equation?right chevron icon

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Q. Does (2,−1)(2, -1) make the equation y=x2−4x+−3y = x^2 - 4x + -3 true?\newlineChoices:\newline(A) yes\newline(B) no
  1. Substitute x-value into equation: Substitute the x-value from the point (2,−1)(2, -1) into the equation y=x2−4x−3y = x^2 - 4x - 3.\newlineCalculation: y=22−4(2)−3=4−8−3=−7y = 2^2 - 4(2) - 3 = 4 - 8 - 3 = -7.
  2. Compare calculated yy-value: Compare the calculated yy-value with the yy-value from the point (2,−1)(2, -1).\newlineThe calculated yy-value is −7-7, but the yy-value from the point is −1-1.

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