Does (2, –1) make the equation y = 5x^2 true? Choices: (A)yes (B)no

Identify Given Point and Equation: Step 1: Identify the given point and equation. Point given: (2, –1) Equation given: y = 5x^2 We need to substitute x = 2 into the equation and check if y equals -1. Substitute x = 2: Step 2: Substitute x = 2 into the equation y = 5x^2. y = 5(2)^2 y = 5 * 4 y = 20 Compare Calculated and Given y-values: Step 3: Compare the calculated y-value with the y-value of the point. Calculated y = 20 Given y = -1 Since 20 does not equal -1, the point (2, –1) does not satisfy the equation.

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Does $(2, -1)$ make the equation $y = 5x^2$ true? $\newline$ Choices: $\newline$ (A) yes $\newline$ (B) no

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Math Problems

Grade 8

Is (x, y) a solution to the nonlinear equation?

Full solution

Q. Does

(2, -1)

make the equation

y = 5x^2

true?

\newline

Choices:

\newline

(A) yes

\newline

(B) no

Identify Given Point and Equation: Step $1$ : Identify the given point and equation. $\newline$ Point given: $(2, -1)$ $\newline$ Equation given: $y = 5x^2$ $\newline$ We need to substitute $x = 2$ into the equation and check if $y$ equals $-1$ .
Substitute $x = 2$ : Step $2$ : Substitute $x = 2$ into the equation $y = 5x^2$ . $\newline$ $y = 5(2)^2$ $\newline$ $y = 5 \times 4$ $\newline$ $y = 20$
Compare Calculated and Given y-values: Step $3$ : Compare the calculated $y$ -value with the $y$ -value of the point. $\newline$ Calculated $y = 20$ $\newline$ Given $y = -1$ $\newline$ Since $20 \neq -1$ , the point $(2, –1)$ does not satisfy the equation.