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solve the equation az+17=−4z−baz+17 = -4z-b

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Full solution

Q. solve the equation az+17=−4z−baz+17 = -4z-b
  1. Move −4z-4z to left: We have the equation az+17=−4z−baz + 17 = -4z - b. To start solving for zz, we need to get all the terms containing zz on one side of the equation. Let's move −4z-4z to the left side by adding 4z4z to both sides of the equation.\newlineaz+17+4z=−4z−b+4zaz + 17 + 4z = -4z - b + 4z
  2. Combine like terms: Now, let's combine like terms on both sides of the equation.\newline(az+4z)+17=−b(az + 4z) + 17 = -b\newlineaa and 44 are coefficients of zz, so we can add them together.\newline(a+4)z+17=−b(a + 4)z + 17 = -b
  3. Isolate the term: Next, we need to isolate the term with zz. We can do this by subtracting 1717 from both sides of the equation.(a+4)z+17−17=−b−17(a + 4)z + 17 - 17 = -b - 17(a+4)z=−b−17(a + 4)z = -b - 17
  4. Divide by coefficient: Finally, to solve for zz, we need to divide both sides of the equation by the coefficient of zz, which is (a+4)(a + 4).\newlinez=−b−17a+4z = \frac{-b - 17}{a + 4}

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