Q. 12t=4v−3−6t=4v+6If (t,v) is the solution to the system of equations, what is the value of t−v?
Write System Equations: Write down the system of equations.We have the following system of equations:1) 12t=4v−32) −6t=4v+6
Solve First Equation for v: Solve the first equation for v.From the first equation, we can express v in terms of t:12t=4v−3Add 3 to both sides:12t+3=4vDivide both sides by 4:(12t+3)/4=vv=3t+3/4
Substitute v into Second Equation: Substitute the expression for v from Step 2 into the second equation.We have v=3t+43, so we substitute this into the second equation:\(-6t = 4(3t + \frac{3}{4}) + 6
Distribute and Simplify: Distribute and simplify the second equation.−6t=4(3t)+4(43)+6−6t=12t+3+6Combine like terms:−6t=12t+9
Solve for t: Solve for t.Subtract 12t from both sides:−6t−12t=9−18t=9Divide both sides by −18:t=−189t=−21
Substitute t into v Expression: Substitute t back into the expression for v from Step 2.v=3t+43v=3(−21)+43v=−23+43
Combine Terms for v: Find a common denominator and combine the terms to solve for v.v=−46+43v=4(−6+3)v=−43
Calculate t−v: Calculate t−v. t−v=(−21)−(−43) Find a common denominator: t−v=(−42)−(−43) t−v=−42+43 t−v=41
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