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Math Problems
Grade 6
Multiply two decimals: where does the decimal point go?
Find the product.
\newline
−
5
⋅
[
1
0
−
2
−
1
]
=
-5 \cdot\left[\begin{array}{cc} 1 & 0 \\ -2 & -1 \end{array}\right]=
−
5
⋅
[
1
−
2
0
−
1
]
=
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Find the difference.
\newline
[
0
2
4
4
]
−
[
2
3
−
2
4
]
=
\left[\begin{array}{ll} 0 & 2 \\ 4 & 4 \end{array}\right]-\left[\begin{array}{cc} 2 & 3 \\ -2 & 4 \end{array}\right]=
[
0
4
2
4
]
−
[
2
−
2
3
4
]
=
Get tutor help
Find the sum.
\newline
[
−
2
0
3
−
2
]
+
[
3
−
1
2
0
]
=
\left[\begin{array}{cc} -2 & 0 \\ 3 & -2 \end{array}\right]+\left[\begin{array}{cc} 3 & -1 \\ 2 & 0 \end{array}\right]=
[
−
2
3
0
−
2
]
+
[
3
2
−
1
0
]
=
Get tutor help
Find the difference.
\newline
[
4
−
2
−
1
4
]
−
[
1
0
0
1
]
=
\left[\begin{array}{cc} 4 & -2 \\ -1 & 4 \end{array}\right]-\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]=
[
4
−
1
−
2
4
]
−
[
1
0
0
1
]
=
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E
=
[
−
1
3
0
4
]
and
B
=
[
0
5
−
2
5
2
2
]
\begin{array}{l} \mathrm{E}=\left[\begin{array}{rr} -1 & 3 \\ 0 & 4 \end{array}\right] \text { and } \mathrm{B}=\left[\begin{array}{llr} 0 & 5 & -2 \\ 5 & 2 & 2 \end{array}\right] \end{array}
E
=
[
−
1
0
3
4
]
and
B
=
[
0
5
5
2
−
2
2
]
\newline
Let
H
=
E
B
\mathrm{H}=\mathrm{EB}
H
=
EB
. Find
H
\mathrm{H}
H
.
\newline
H
=
\mathbf{H}=
H
=
Get tutor help
Evaluate.
\newline
(
−
2
1
4
)
2
=
\left(-2 \frac{1}{4}\right)^{2}=
(
−
2
4
1
)
2
=
Get tutor help
Evaluate.
\newline
(
−
1
1
4
)
2
=
\left(-1 \frac{1}{4}\right)^{2}=
(
−
1
4
1
)
2
=
Get tutor help
Solve for
u
u
u
:
\newline
−
10.74
=
u
−
(
−
11
)
u
=
□
\begin{array}{l} -10.74=u-(-11) \\ u=\square \end{array}
−
10.74
=
u
−
(
−
11
)
u
=
□
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Solve for
q
q
q
:
\newline
−
9
=
q
−
4.8
q
=
□
\begin{array}{l} -9=q-4.8 \\ q=\square \end{array}
−
9
=
q
−
4.8
q
=
□
Get tutor help
Solve for
s
s
s
:
\newline
−
0.2
=
s
+
(
−
0.8
)
s
=
□
\begin{array}{l} -0.2=s+(-0.8) \\ s=\square \end{array}
−
0.2
=
s
+
(
−
0.8
)
s
=
□
Get tutor help
Solve for
d
d
d
:
\newline
d
+
(
−
5.004
)
=
2.826
d
=
□
\begin{array}{l} d+(-5.004)=2.826 \\ d=\square \end{array}
d
+
(
−
5.004
)
=
2.826
d
=
□
Get tutor help
Solve for
a
a
a
:
\newline
a
−
(
−
3.75
)
=
6.11
a
=
□
\begin{array}{l} a-(-3.75)=6.11 \\ a=\square \end{array}
a
−
(
−
3.75
)
=
6.11
a
=
□
Get tutor help
Solve for
f
f
f
:
\newline
f
+
1
4
=
−
7
2
f
=
□
\begin{array}{l} f+\frac{1}{4}=-\frac{7}{2} \\ f=\square \end{array}
f
+
4
1
=
−
2
7
f
=
□
Get tutor help
Solve for
ℓ
\ell
ℓ
:
\newline
(
−
7.4
)
+
ℓ
=
9.11
ℓ
=
□
\begin{array}{l} (-7.4)+\ell=9.11 \\ \ell=\square \end{array}
(
−
7.4
)
+
ℓ
=
9.11
ℓ
=
□
Get tutor help
Solve for
h
h
h
:
\newline
h
−
(
−
2.22
)
=
−
7.851
h
=
□
\begin{array}{l} h-(-2.22)=-7.851 \\ h=\square \end{array}
h
−
(
−
2.22
)
=
−
7.851
h
=
□
Get tutor help
Solve for
d
d
d
.
\newline
41
=
12
d
−
7
d
=
□
\begin{array}{l} 41=12 d-7 \\ d=\square \end{array}
41
=
12
d
−
7
d
=
□
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Solve for
p
p
p
.
\newline
9
(
p
−
4
)
=
−
18
p
=
□
\begin{array}{l} 9(p-4)=-18 \\ p=\square \end{array}
9
(
p
−
4
)
=
−
18
p
=
□
Get tutor help
Solve for
h
h
h
.
\newline
h
6
−
1
=
−
3
h
=
□
\begin{array}{l} \frac{h}{6}-1=-3 \\ h=\square \end{array}
6
h
−
1
=
−
3
h
=
□
Get tutor help
Solve for
k
k
k
.
\newline
k
4
+
3
=
14
k
=
□
\begin{array}{l} \frac{k}{4}+3=14 \\ k=\square \end{array}
4
k
+
3
=
14
k
=
□
Get tutor help
Solve for
n
n
n
.
\newline
24
=
3
(
n
−
5
)
n
=
□
\begin{array}{l} 24=3(n-5) \\ n=\square \end{array}
24
=
3
(
n
−
5
)
n
=
□
Get tutor help
Solve for
m
m
m
.
\newline
2
=
m
2
−
7
m
=
\begin{array}{l} 2=\frac{m}{2}-7 \\ m= \end{array}
2
=
2
m
−
7
m
=
Get tutor help
Reduce to simplest form.
\newline
5
8
−
(
−
7
2
)
=
\frac{5}{8}-\left(-\frac{7}{2}\right)=
8
5
−
(
−
2
7
)
=
Get tutor help
Reduce to simplest form.
\newline
−
9
12
−
(
−
7
4
)
=
-\frac{9}{12}-\left(-\frac{7}{4}\right)=
−
12
9
−
(
−
4
7
)
=
Get tutor help
Reduce to simplest form.
\newline
9
5
−
(
−
6
10
)
=
\frac{9}{5}-\left(-\frac{6}{10}\right)=
5
9
−
(
−
10
6
)
=
Get tutor help
Solve the equation.
\newline
9
a
=
81
a
=
□
\begin{array}{l} 9 a=81 \\ a=\square \end{array}
9
a
=
81
a
=
□
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Solve the equation.
\newline
5
=
g
8
g
=
□
\begin{array}{l} 5=\frac{g}{8} \\ g=\square \end{array}
5
=
8
g
g
=
□
Get tutor help
Solve the equation.
\newline
d
4
=
9
d
=
□
\begin{array}{l} \frac{d}{4}=9 \\ d=\square \end{array}
4
d
=
9
d
=
□
Get tutor help
Solve the equation.
\newline
7
2
=
7
10
h
h
=
\begin{array}{l} \frac{7}{2}=\frac{7}{10} h \\ h= \end{array}
2
7
=
10
7
h
h
=
Get tutor help
Solve the equation.
\newline
2
=
n
3
n
=
□
\begin{array}{l} 2=\frac{n}{3} \\ n=\square \end{array}
2
=
3
n
n
=
□
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Solve the equation.
\newline
2
3
p
=
5
p
=
\begin{array}{l} \frac{2}{3} p=5 \\ p= \end{array}
3
2
p
=
5
p
=
Get tutor help
Solve the equation.
\newline
9
=
9
m
m
=
□
\begin{array}{l} 9=9 m \\ m=\square \end{array}
9
=
9
m
m
=
□
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Solve the equation.
\newline
w
5
=
3
w
=
□
\begin{array}{l} \frac{w}{5}=3 \\ w=\square \end{array}
5
w
=
3
w
=
□
Get tutor help
Solve the equation.
\newline
51
=
3
k
k
=
□
\begin{array}{l} 51=3 k \\ k=\square \end{array}
51
=
3
k
k
=
□
Get tutor help
Solve the equation.
\newline
12
j
=
21
j
=
□
\begin{array}{l} 12 j=21 \\ j=\square \end{array}
12
j
=
21
j
=
□
Get tutor help
Solve the equation.
\newline
1.2
=
1.5
k
k
=
\begin{array}{l} 1.2=1.5 k \\ k= \end{array}
1.2
=
1.5
k
k
=
Get tutor help
Solve the equation.
\newline
40
=
x
0.3
x
=
\begin{array}{l} 40=\frac{x}{0.3} \\ x= \end{array}
40
=
0.3
x
x
=
Get tutor help
Solve the equation.
\newline
5
c
=
13
c
=
□
\begin{array}{l} 5 c=13 \\ c=\square \end{array}
5
c
=
13
c
=
□
Get tutor help
Solve the equation.
\newline
6
=
3
5
y
y
=
\begin{array}{l} 6=\frac{3}{5} y \\ y= \end{array}
6
=
5
3
y
y
=
Get tutor help
Solve the equation.
\newline
4
3
b
=
4
5
b
=
\begin{array}{l} \frac{4}{3} b=\frac{4}{5} \\ b= \end{array}
3
4
b
=
5
4
b
=
Get tutor help
Solve the equation.
\newline
2.5
=
w
2.8
w
=
\begin{array}{l} 2.5=\frac{w}{2.8} \\ w= \end{array}
2.5
=
2.8
w
w
=
Get tutor help
Solve the equation.
\newline
9
=
4
t
t
=
□
\begin{array}{l} 9=4 t \\ t=\square \end{array}
9
=
4
t
t
=
□
Get tutor help
Solve the equation.
\newline
b
6
=
3
b
=
□
\begin{array}{l} \frac{b}{6}=3 \\ b=\square \end{array}
6
b
=
3
b
=
□
Get tutor help
Solve for
z
z
z
.
\newline
z
12
=
4
5
z
=
\begin{array}{l} \frac{z}{12}=\frac{4}{5} \\ z= \end{array}
12
z
=
5
4
z
=
Get tutor help
Solve for
z
z
z
.
\newline
4
z
=
12
5
z
=
\begin{array}{l} \frac{4}{z}=\frac{12}{5} \\ z= \end{array}
z
4
=
5
12
z
=
Get tutor help
Solve the equation.
\newline
a
7
=
9
a
=
□
\begin{array}{l} \frac{a}{7}=9 \\ a=\square \end{array}
7
a
=
9
a
=
□
Get tutor help
Solve the equation.
\newline
2
=
f
8
f
=
□
\begin{array}{l} 2=\frac{f}{8} \\ f=\square \end{array}
2
=
8
f
f
=
□
Get tutor help
Solve the equation.
\newline
6
=
m
8
m
=
□
\begin{array}{l} 6=\frac{m}{8} \\ m=\square \end{array}
6
=
8
m
m
=
□
Get tutor help
Solve the equation.
\newline
5
6
w
=
10
3
w
=
\begin{array}{l} \frac{5}{6} w=\frac{10}{3} \\ w= \end{array}
6
5
w
=
3
10
w
=
Get tutor help
Solve the equation.
\newline
6
=
k
9
k
=
□
\begin{array}{l} 6=\frac{k}{9} \\ k=\square \end{array}
6
=
9
k
k
=
□
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Solve the equation.
\newline
5
d
=
1
2
d
=
□
\begin{array}{l} 5 d=\frac{1}{2} \\ d=\square \end{array}
5
d
=
2
1
d
=
□
Get tutor help
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