Solve for ℓ : {:[(-7.4)+ℓ=9.11],[ℓ=◻]:}

Addition to cancel -7.4: We are given the equation (-7.4) + ℓ = 9.11. To solve for ℓ, we need to isolate ℓ on one side of the equation. We can do this by adding 7.4 to both sides of the equation to cancel out the -7.4 on the left side. Calculation: ℓ = 9.11 + 7.4Perform addition to find ℓ: Now we perform the addition on the right side of the equation to find the value of ℓ. Calculation: ℓ = 9.11 + 7.4 = 16.51

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Solve for
ℓ :

{:[(-7.4)+ℓ=9.11],[ℓ=◻]:}

Solve for $\ell$ : $\newline$ $\begin{array}{l} (-7.4)+\ell=9.11 \\ \ell=\square \end{array}$

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Math Problems

Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. Solve for

\ell

\newline

\begin{array}{l} (-7.4)+\ell=9.11 \\ \ell=\square \end{array}

Addition to cancel $-7.4$ : We are given the equation $(-7.4) + \ell = 9.11$ . To solve for $\ell$ , we need to isolate $\ell$ on one side of the equation. We can do this by adding $7.4$ to both sides of the equation to cancel out the $-7.4$ on the left side. $\newline$ Calculation: $\ell = 9.11 + 7.4$
Perform addition to find $\ell$ : Now we perform the addition on the right side of the equation to find the value of $\ell$ . $\newline$ Calculation: $\ell = 9.11 + 7.4 = 16.51$