Solve for d. {:[41=12 d-7],[d=◻]:}

Start Equation: Start with the given equation 41 = 12d - 7.Add 7: Add 7 to both sides of the equation to isolate the term with d on one side. 41 + 7 = 12d - 7 + 7 48 = 12dDivide by 12: Divide both sides of the equation by 12 to solve for d. 48 / 12 = 12d / 12 4 = d

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Solve for $d$ . $\newline$ $\begin{array}{l} 41=12 d-7 \\ d=\square \end{array}$

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Grade 6

Multiply two decimals: where does the decimal point go?

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Q. Solve for

d

\newline

\begin{array}{l} 41=12 d-7 \\ d=\square \end{array}

Start Equation: Start with the given equation $41 = 12d - 7$ .
Add $7$ : Add $7$ to both sides of the equation to isolate the term with $d$ on one side. $\newline$ $41 + 7 = 12d - 7 + 7$ $\newline$ $48 = 12d$
Divide by $12$ : Divide both sides of the equation by $12$ to solve for $d$ . $\frac{48}{12} = \frac{12d}{12}$ $4 = d$