Solve for n. {:[24=3(n-5)],[n=◻]:}

Distribute and Simplify: We are given a system of equations: \[ 24 = 3(n - 5) \] \[ n = \square \] We need to solve the first equation for n.Addition to Isolate n: Distribute the 3 into the parentheses in the equation $ 24 = 3(n - 5) $. \[ 24 = 3n - 15 \]Divide to Solve for n: Add 15 to both sides of the equation to isolate the term with n on one side. \[ 24 + 15 = 3n - 15 + 15 \] \[ 39 = 3n \]Divide both sides of the equation by 3 to solve for n. \[ \frac{39}{3} = \frac{3n}{3} \] \[ 13 = n \]

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Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. Solve for

n

\newline

\begin{array}{l} 24=3(n-5) \\ n=\square \end{array}

Distribute and Simplify: We are given a system of equations: $\newline$ $24 = 3(n - 5)$ $\newline$ $n = \square$ $\newline$ We need to solve the first equation for n.
Addition to Isolate n: Distribute the $3$ into the parentheses in the equation $24 = 3(n - 5)$ . $\newline$ $24 = 3n - 15$
Divide to Solve for n: Add $15$ to both sides of the equation to isolate the term with n on one side. $\newline$ $24 + 15 = 3n - 15 + 15$ $\newline$ $39 = 3n$
Divide to Solve for n: Add $15$ to both sides of the equation to isolate the term with n on one side. $\newline$ $24 + 15 = 3n - 15 + 15$ $\newline$ $39 = 3n$ Divide both sides of the equation by $3$ to solve for n. $\newline$ $\frac{39}{3} = \frac{3n}{3}$ $\newline$ $13 = n$