Solve for h. {:[(h)/(6)-1=-3],[h=]:}

Add 1 to isolate h: Add 1 to both sides of the equation to isolate the term with h. (h/6) - 1 + 1 = -3 + 1Simplify both sides: Simplify both sides of the equation. (h/6) = -2Multiply by 6: Multiply both sides of the equation by 6 to solve for h. 6 * (h/6) = -2 * 6Simplify to find h: Simplify both sides of the equation to find the value of h. h = -12

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for $h$ . $\newline$ $\begin{array}{l} \frac{h}{6}-1=-3 \\ h=\square \end{array}$

View step-by-step help

Home

Math Problems

Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. Solve for

h

\newline

\begin{array}{l} \frac{h}{6}-1=-3 \\ h=\square \end{array}

Add $1$ to isolate h: Add $1$ to both sides of the equation to isolate the term with h. $\newline$ $(\frac{h}{6}) - 1 + 1 = -3 + 1$
Simplify both sides: Simplify both sides of the equation. $\frac{h}{6} = -2$
Multiply by $6$ : Multiply both sides of the equation by $6$ to solve for $h$ . $6 \times \left(\frac{h}{6}\right) = -2 \times 6$
Simplify to find $h$ : Simplify both sides of the equation to find the value of $h$ . $h = -12$