Solve for m. {:[2=(m)/(2)-7],[m=]:}

Identify Equation: Identify the first equation in the system. The first equation is 2 = (m/2) - 7.Isolate m: Isolate m in the first equation. To do this, we will add 7 to both sides of the equation to get m/2 on one side. 2 + 7 = (m/2) - 7 + 7 9 = m/2Multiply by 2: Multiply both sides of the equation by 2 to solve for m. 2 * 9 = m/2 * 2 18 = mCheck Solution: Check the solution by substituting m back into the original equation. 2 = (18/2) - 7 2 = 9 - 7 2 = 2 The solution m = 18 satisfies the first equation.Final Solution: Since the second part of the system is simply m =, we have already found the value of m that satisfies the first equation, and there are no further restrictions on m. Therefore, m = 18 is the solution to the system.

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Solve for $m$ . $\newline$ $\begin{array}{l} 2=\frac{m}{2}-7 \\ m= \end{array}$

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Grade 6

Multiply two decimals: where does the decimal point go?

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Q. Solve for

m

\newline

\begin{array}{l} 2=\frac{m}{2}-7 \\ m= \end{array}

Identify Equation: Identify the first equation in the system. $\newline$ The first equation is $2 = (m/2) - 7$ .
Isolate $m$ : Isolate $m$ in the first equation. $\newline$ To do this, we will add $7$ to both sides of the equation to get $\frac{m}{2}$ on one side. $\newline$ $2 + 7 = \left(\frac{m}{2}\right) - 7 + 7$ $\newline$ $9 = \frac{m}{2}$
Multiply by $2$ : Multiply both sides of the equation by $2$ to solve for $m$ . $2 \times 9 = \frac{m}{2} \times 2$ $18 = m$
Check Solution: Check the solution by substituting $m$ back into the original equation. $\newline$ $2 = (18/2) - 7$ $\newline$ $2 = 9 - 7$ $\newline$ $2 = 2$ $\newline$ The solution $m = 18$ satisfies the first equation.
Final Solution: Since the second part of the system is simply $m =$ , we have already found the value of $m$ that satisfies the first equation, and there are no further restrictions on $m$ . Therefore, $m = 18$ is the solution to the system.