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Math Problems
Algebra 1
Solve linear equations: mixed review
Solve for a.
\newline
8
=
−
5
+
a
8=-5+a
8
=
−
5
+
a
\newline
Answer:
a
=
a=
a
=
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Solve for
c
\mathrm{c}
c
.
\newline
c
+
3
=
−
7
c+3=-7
c
+
3
=
−
7
\newline
Answer:
c
=
c=
c
=
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Solve for
c
\mathrm{c}
c
.
\newline
c
−
9
=
−
1
c-9=-1
c
−
9
=
−
1
\newline
Answer:
c
=
c=
c
=
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Solve for
s
\mathrm{s}
s
.
\newline
s
+
5
=
−
6
s+5=-6
s
+
5
=
−
6
\newline
Answer:
s
=
s=
s
=
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Solve for
x
x
x
.
\newline
85
=
10
11
x
+
15
85=\frac{10}{11} x+15
85
=
11
10
x
+
15
\newline
Answer:
x
=
x=
x
=
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Solve for
y
y
y
.
\newline
−
5
6
y
+
9
=
34
-\frac{5}{6} y+9=34
−
6
5
y
+
9
=
34
\newline
Answer:
y
=
y=
y
=
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Solve for
y
y
y
.
\newline
12
−
2
7
y
=
30
12-\frac{2}{7} y=30
12
−
7
2
y
=
30
\newline
Answer:
y
=
y=
y
=
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Solve for
b
b
b
.
\newline
7
+
7
11
b
=
35
7+\frac{7}{11} b=35
7
+
11
7
b
=
35
\newline
Answer:
b
=
b=
b
=
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Solve for
b
b
b
.
\newline
9
+
4
5
b
=
45
9+\frac{4}{5} b=45
9
+
5
4
b
=
45
\newline
Answer:
b
=
b=
b
=
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Solve for
b
b
b
.
\newline
4
11
b
−
8
=
16
\frac{4}{11} b-8=16
11
4
b
−
8
=
16
\newline
Answer:
b
=
b=
b
=
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Solve for
a
a
a
.
\newline
−
11
=
1
3
a
−
25
-11=\frac{1}{3} a-25
−
11
=
3
1
a
−
25
\newline
Answer:
a
=
a=
a
=
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Solve for
z
z
z
.
\newline
−
15
+
3
10
z
=
−
12
-15+\frac{3}{10} z=-12
−
15
+
10
3
z
=
−
12
\newline
Answer:
z
=
z=
z
=
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Solve for
z
z
z
.
\newline
−
11
12
z
+
16
=
49
-\frac{11}{12} z+16=49
−
12
11
z
+
16
=
49
\newline
Answer:
z
=
z=
z
=
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Solve for
x
x
x
.
\newline
17
+
1
12
x
=
24
17+\frac{1}{12} x=24
17
+
12
1
x
=
24
\newline
Answer:
x
=
x=
x
=
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Solve for
y
y
y
.
\newline
20
=
−
15
+
7
11
y
20=-15+\frac{7}{11} y
20
=
−
15
+
11
7
y
\newline
Answer:
y
=
y=
y
=
Get tutor help
Solve for
c
c
c
.
\newline
1
6
c
+
14
=
18
\frac{1}{6} c+14=18
6
1
c
+
14
=
18
\newline
Answer:
c
=
c=
c
=
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Solve for
c
c
c
.
\newline
31
=
5
8
c
+
21
31=\frac{5}{8} c+21
31
=
8
5
c
+
21
\newline
Answer:
c
=
c=
c
=
Get tutor help
Solve for
x
x
x
.
\newline
−
3
10
x
+
25
=
49
-\frac{3}{10} x+25=49
−
10
3
x
+
25
=
49
\newline
Answer:
x
=
x=
x
=
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Solve for
x
x
x
.
\newline
3
x
−
15
=
0
3x-15=0
3
x
−
15
=
0
\newline
x
=
□
x=\square
x
=
□
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Solve for
q
q
q
.
\newline
14
=
q
3
+
12
14 = \frac{q}{3} + 12
14
=
3
q
+
12
\newline
q
=
q =
q
=
\newline
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Solve for
r
r
r
.
\newline
r
9
−
65
=
−
60
\frac{r}{9}-65=-60
9
r
−
65
=
−
60
\newline
r
=
r=
r
=
\newline
Get tutor help
Find the value of
x
x
x
that solves the equation
ln
(
x
−
1
)
+
3
ln
2
=
ln
10
\ln (x-1)+3 \ln 2=\ln 10
ln
(
x
−
1
)
+
3
ln
2
=
ln
10
.
\newline
Answer:
x
=
x=
x
=
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lim
x
→
5
12
x
−
60
x
2
−
6
x
+
5
=
\lim _{x \rightarrow 5} \frac{12 x-60}{x^{2}-6 x+5}=
lim
x
→
5
x
2
−
6
x
+
5
12
x
−
60
=
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Solve for
b
b
b
.
\newline
−
11
b
+
7
=
40
b
=
□
\begin{array}{l} -11 b+7=40 \\ b=\square \end{array}
−
11
b
+
7
=
40
b
=
□
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Solve for
z
z
z
.
\newline
42
=
−
7
(
z
−
3
)
42=-7(z-3)
42
=
−
7
(
z
−
3
)
\newline
z
=
z=
z
=
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Solve for
n
n
n
.
\newline
7
n
−
4
=
31
7 n-4=31
7
n
−
4
=
31
\newline
n
=
n=
n
=
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Solve the equation.
\newline
z
2
=
6
\frac{z}{2}=6
2
z
=
6
\newline
z
=
z=
z
=
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Solve the equation.
\newline
c
8
=
9
\frac{c}{8}=9
8
c
=
9
\newline
c
=
c=
c
=
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Solve the equation.
\newline
1
2
=
2
3
x
\frac{1}{2}=\frac{2}{3} x
2
1
=
3
2
x
\newline
x
=
x=
x
=
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Solve the equation.
\newline
r
0.4
=
1.5
\frac{r}{0.4}=1.5
0.4
r
=
1.5
\newline
r
=
r=
r
=
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Solve the equation.
\newline
g
4
=
3.2
\frac{g}{4}=3.2
4
g
=
3.2
\newline
g
=
g=
g
=
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Solve the equation.
\newline
1
2
a
=
11
\frac{1}{2} a=11
2
1
a
=
11
\newline
a
=
a=
a
=
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Solve the equation.
\newline
3
2
=
4
x
\frac{3}{2}=4 x
2
3
=
4
x
\newline
x
=
x=
x
=
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Solve for
c
c
c
.
\newline
5
4
=
−
4
c
+
1
4
\frac{5}{4}=-4 c+\frac{1}{4}
4
5
=
−
4
c
+
4
1
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Solve for
p
p
p
.
\newline
−
5
(
p
+
3
5
)
=
−
4
-5\left(p+\frac{3}{5}\right)=-4
−
5
(
p
+
5
3
)
=
−
4
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Solve for
m
m
m
.
\newline
m
9
+
2
3
=
7
3
\frac{m}{9}+\frac{2}{3}=\frac{7}{3}
9
m
+
3
2
=
3
7
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Solve for
y
y
y
.
\newline
−
3
=
7
(
y
−
9
7
)
-3=7\left(y-\frac{9}{7}\right)
−
3
=
7
(
y
−
7
9
)
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Solve for
g
g
g
.
\newline
−
0.4
=
g
3
−
0.9
-0.4=\frac{g}{3}-0.9
−
0.4
=
3
g
−
0.9
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Solve for
h
h
h
.
\newline
3
7
=
h
14
−
2
7
\frac{3}{7}=\frac{h}{14}-\frac{2}{7}
7
3
=
14
h
−
7
2
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Solve for
e
e
e
.
\newline
4
3
=
−
6
e
−
5
3
\frac{4}{3}=-6 e-\frac{5}{3}
3
4
=
−
6
e
−
3
5
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Solve for
x
x
x
.
\newline
−
4.5
=
−
0.5
(
x
−
7.1
)
-4.5=-0.5(x-7.1)
−
4.5
=
−
0.5
(
x
−
7.1
)
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Solve for
n
n
n
.
\newline
n
5
+
0.6
=
2
\frac{n}{5}+0.6=2
5
n
+
0.6
=
2
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Solve for
j
j
j
.
\newline
−
1
3
=
j
4
−
10
3
-\frac{1}{3}=\frac{j}{4}-\frac{10}{3}
−
3
1
=
4
j
−
3
10
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Solve the equation.
\newline
e
3
=
7
\frac{e}{3}=7
3
e
=
7
\newline
e
=
e=
e
=
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Solve the equation.
\newline
y
8
=
5
\frac{y}{8}=5
8
y
=
5
\newline
y
=
y=
y
=
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Solve for
t
t
t
.
\newline
t
+
9
t
+
4
=
5
\frac{t+9}{t+4}=5
t
+
4
t
+
9
=
5
\newline
t
=
t=
t
=
Get tutor help
Which value of
x
x
x
makes
7
+
5
(
x
−
3
)
=
22
7+5(x-3)=22
7
+
5
(
x
−
3
)
=
22
a true statement?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
=
4
x=4
x
=
4
\newline
(B)
x
=
5
x=5
x
=
5
\newline
(C)
x
=
6
x=6
x
=
6
\newline
(D)
x
=
7
x=7
x
=
7
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4
7
÷
5
=
\frac{4}{7} \div 5=
7
4
÷
5
=
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4
5
÷
8
=
\frac{4}{5} \div 8=
5
4
÷
8
=
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What is the slope of the line?
\newline
7
x
+
2
y
=
5
7 x+2 y=5
7
x
+
2
y
=
5
\newline
Choose
1
1
1
answer:
\newline
(A)
2
7
\frac{2}{7}
7
2
\newline
(B)
−
2
7
-\frac{2}{7}
−
7
2
\newline
(c)
−
7
2
-\frac{7}{2}
−
2
7
\newline
(D)
7
2
\frac{7}{2}
2
7
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