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Solve for h. (3)/(7)=(h)/( 14)-(2)/(7)

Solve for h h .\newline37=h14−27 \frac{3}{7}=\frac{h}{14}-\frac{2}{7}

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Full solution

Q. Solve for h h .\newline37=h14−27 \frac{3}{7}=\frac{h}{14}-\frac{2}{7}
  1. Isolate variable hh: First, we want to isolate the variable hh on one side of the equation. To do this, we can start by adding 27\frac{2}{7} to both sides of the equation to move the constant term to the left side.\newline37+27=h14\frac{3}{7} + \frac{2}{7} = \frac{h}{14}
  2. Combine like terms: Now, we combine the like terms on the left side of the equation.\newline(37)+(27)=(57)(\frac{3}{7}) + (\frac{2}{7}) = (\frac{5}{7})\newlineSo, the equation now is:\newline(57)=(h14)(\frac{5}{7}) = (\frac{h}{14})
  3. Get rid of denominator: To solve for hh, we need to get rid of the denominator 1414. We can do this by multiplying both sides of the equation by 1414.14×(57)=14×(h14)14 \times \left(\frac{5}{7}\right) = 14 \times \left(\frac{h}{14}\right)
  4. Simplify left side: When we multiply the left side, we simplify the fraction by canceling out the common factor of 77 in the numerator and denominator.14×(57)=2×5=1014 \times \left(\frac{5}{7}\right) = 2 \times 5 = 10On the right side, the 1414 in the numerator and denominator cancel each other out, leaving us with:10=h10 = h

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