Solve for h. (3)/(7)=(h)/( 14)-(2)/(7)

Isolate variable h: First, we want to isolate the variable h on one side of the equation. To do this, we can start by adding (2/7) to both sides of the equation to move the constant term to the left side. (3/7) + (2/7) = (h/14)Combine like terms: Now, we combine the like terms on the left side of the equation. (3/7) + (2/7) = (5/7) So, the equation now is: (5/7) = (h/14)Get rid of denominator: To solve for h, we need to get rid of the denominator 14. We can do this by multiplying both sides of the equation by 14. 14 * (5/7) = 14 * (h/14)Simplify left side: When we multiply the left side, we simplify the fraction by canceling out the common factor of 7 in the numerator and denominator. 14 * (5/7) = 2 * 5 = 10 On the right side, the 14 in the numerator and denominator cancel each other out, leaving us with: 10 = h

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Algebra 1

Solve linear equations: mixed review

Full solution

Q. Solve for

h

\newline

\frac{3}{7}=\frac{h}{14}-\frac{2}{7}

Isolate variable $h$ : First, we want to isolate the variable $h$ on one side of the equation. To do this, we can start by adding $\frac{2}{7}$ to both sides of the equation to move the constant term to the left side. $\newline$ $\frac{3}{7} + \frac{2}{7} = \frac{h}{14}$
Combine like terms: Now, we combine the like terms on the left side of the equation. $\newline$ $(\frac{3}{7}) + (\frac{2}{7}) = (\frac{5}{7})$ $\newline$ So, the equation now is: $\newline$ $(\frac{5}{7}) = (\frac{h}{14})$
Get rid of denominator: To solve for $h$ , we need to get rid of the denominator $14$ . We can do this by multiplying both sides of the equation by $14$ . $14 \times \left(\frac{5}{7}\right) = 14 \times \left(\frac{h}{14}\right)$
Simplify left side: When we multiply the left side, we simplify the fraction by canceling out the common factor of $7$ in the numerator and denominator. $14 \times \left(\frac{5}{7}\right) = 2 \times 5 = 10$ On the right side, the $14$ in the numerator and denominator cancel each other out, leaving us with: $10 = h$