Solve for y. 12-(2)/(7)y=30 Answer: y=

Isolate y term: First, we want to isolate the term containing y on one side of the equation. 12 - (2/7)y = 30 Subtract 12 from both sides to move the constant term to the right side. 12 - 12 - (2/7)y = 30 - 12Simplify equation: Now, simplify both sides of the equation. 0 - (2/7)y = 18 -(2/7)y = 18Get rid of fraction: Next, we want to solve for y by getting rid of the fraction. Multiply both sides by -7/2 to cancel out the fraction on the left side. (-7/2) * (-(2/7)y) = 18 * (-7/2)Solve for y: Simplify both sides of the equation. y = 18 * (-7/2) y = -63

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Solve for $y$ . $\newline$ $12-\frac{2}{7} y=30$ $\newline$ Answer: $y=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

y

\newline

12-\frac{2}{7} y=30

\newline

Answer:

y=

Isolate y term: First, we want to isolate the term containing $y$ on one side of the equation. $12 - \left(\frac{2}{7}\right)y = 30$ Subtract $12$ from both sides to move the constant term to the right side. $12 - 12 - \left(\frac{2}{7}\right)y = 30 - 12$
Simplify equation: Now, simplify both sides of the equation. $\newline$ $0 - \frac{2}{7}y = 18$ $\newline$ $-\frac{2}{7}y = 18$
Get rid of fraction: Next, we want to solve for $y$ by getting rid of the fraction. Multiply both sides by $-\frac{7}{2}$ to cancel out the fraction on the left side. $\newline$ \left(-\frac{$7$}{$2$}\right) \times \left(-\frac{$2$}{$7$}y\right) = \(18 \times \left(-\frac{ $7$ }{ $2$ }\right)
Solve for y: Simplify both sides of the equation. $\newline$ $y = 18 \times \left(-\frac{7}{2}\right)$ $\newline$ $y = -63$