Solve for b. {:[-11 b+7=40],[b=◻]:}

Isolate b in first equation: First, let's isolate b in the first equation. -11b + 7 = 40 Subtract 7 from both sides to get the b term by itself. -11b + 7 - 7 = 40 - 7 -11b = 33Divide both sides: Now, divide both sides by -11 to solve for b. -11b / -11 = 33 / -11 b = -3

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Solve for $b$ . $\newline$ $\begin{array}{l} -11 b+7=40 \\ b=\square \end{array}$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

b

\newline

\begin{array}{l} -11 b+7=40 \\ b=\square \end{array}

Isolate $b$ in first equation: First, let's isolate $b$ in the first equation. $\newline$ $-11b + 7 = 40$ $\newline$ Subtract $7$ from both sides to get the $b$ term by itself. $\newline$ $-11b + 7 - 7 = 40 - 7$ $\newline$ $-11b = 33$
Divide both sides: Now, divide both sides by $-11$ to solve for $b$ . $\frac{-11b}{-11} = \frac{33}{-11}$ $b = -3$